Given n non-negative integers a1, a2, ..., an, where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of line i is at (i, ai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.
Note: You may not slant the container.
贪心策略:两端设置围栏,无论如何注水,水只要不超过其中较短的那一根围栏即可,中间的柱子可以忽略。
相继缩短距离,较短一端的柱子换成向里的一根。
例如: height[left] <= height[right] : left = left+1;
反之, right = right-1;
1 class Solution { 2 public: 3 int maxArea(vector<int> &height) { 4 int ans=0,left=0,right=height.size()-1,contain; 5 while(left<right) 6 { 7 contain = (right-left)*min(height[right],height[left]); 8 ans = max(contain, ans); 9 height[left]<=height[right]?left++:right--; 10 } 11 return ans; 12 } 13 };