【python】正则表达式相关

注意：Python3.X 的print要有括号， Python 2.x的不需要

放上学习时写的例子：

import re

m = re.match(r'(w+) (w+)(?P<sign>.*)', 'hello world!')


print("m.string:", m.string)
print("m.re:", m.re)
print("m.pos:", m.pos)
print("m.endpos:", m.endpos)
print("m.lastindex:", m.lastindex)
print("m.lastgroup:", m.lastgroup)

print("m.group():", m.group())
print("m.group(1,2):", m.group(1,2))

print("m.groups():", m.groups())
print("m.groupdict():", m.groupdict())

print("m.start(2):", m.start(2))

print("m.span(2):", m.span(2))

print(r"m.expand(r'g gg'):", m.expand(r'2 13'))


#search 不一定从第0位开始匹配

pattern = re.compile(r'world')

match = re.search(pattern, 'hello world!')
if match:
    print(match.group())
 



#split 已pattern分割字符串
pattern = re.compile(r'd+')
print(re.split(pattern, 'one1two2three33four4'))

#findall 以列表形式返回全部能匹配的子串

pattern = re.compile(r'd+')
print(re.findall(pattern, 'one1two2three33four4'))

#finditer 返回一个顺序访问每一个匹配结果的迭代器
pattern = re.compile(r'd+')

for m in re.finditer(pattern, 'one1two2three3four4'):
    print(m.group())


#替换
pattern = re.compile(r'(w+) (w+)')
s = 'i say, hello world!'



print(re.sub(pattern, r'2 1', s))


def func(m):
    return m.group(1).title() + ' ' + m.group(2).title()



print(re.sub(pattern, func, s))
    
#subn 比替换多返回了一个替换次数

print(re.subn(pattern, func, s))