len(a) |
the number of items in a 得到字典中元素的个数
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a[k] |
the item of a with key k 取得键K所对应的值
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(1), (10) |
a[k] = v |
set a[k] to v 设定键k所对应的值成为v
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del a[k] |
remove a[k] from a 从字典中删除键为k的元素
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(1) |
a.clear() |
remove all items from a 清空整个字典
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a.copy() |
a (shallow) copy of a 得到字典副本
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k in a |
True if a has a key k, else False 字典中存在键k则为返回True，没有则返回False
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(2) |
k not in a |
Equivalent to not k in a 字典中不存在键k则为返回true,反之返回False |
(2) |
a.has_key(k) |
Equivalent to k in a, use that form in new code 等价于k in a
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a.items() |
a copy of a's list of (key, value) pairs 得到一个键，值的list
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(3) |
a.keys() |
a copy of a's list of keys 得到键的list
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(3) |
a.update([b]) |
updates (and overwrites) key/value pairs from b从b字典中更新a字典，如果键相同则更新，a中不存在则追加 |
(9) |
a.fromkeys(seq[, value]) |
Creates a new dictionary with keys from seq and values set to value
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(7) |
a.values() |
a copy of a's list of values |
(3) |
a.get(k[, x]) |
a[k] if k in a, else x |
(4) |
a.setdefault(k[, x]) |
a[k] if k in a, else x (also setting it) |
(5) |
a.pop(k[, x]) |
a[k] if k in a, else x (and remove k) |
(8) |
a.popitem() |
remove and return an arbitrary (key, value) pair |
(6) |
a.iteritems() |
return an iterator over (key, value) pairs |
(2), (3) |
a.iterkeys() |
return an iterator over the mapping's keys |
(2), (3) |
a.itervalues() |
return an iterator over the mapping's values |
(2), (3) |