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  • UVa 12333 Revenge of Fibonacci (字典树+大数)

    题意:给定一个长度小于40的序列,问你那是Fib数列的哪一项的前缀。

    析:首先用大数把Fib数列的前100000-1项算出来,注意,一定不能是100000,要不然会WA的,然后每个数取前40位,不足40位的全取,然后插入到字典树上,

    并用一个数组标记是哪一项,最后查询的时候,如果查不到就是无解,否则输出答案。

    在我电脑上跑了10秒多,交上去才1秒多。

    代码如下:

    #pragma comment(linker, "/STACK:1024000000,1024000000")
    #include <cstdio>
    #include <string>
    #include <cstdlib>
    #include <cmath>
    #include <iostream>
    #include <cstring>
    #include <set>
    #include <queue>
    #include <algorithm>
    #include <vector>
    #include <map>
    #include <cctype>
    #include <cmath>
    #include <stack>
    #define debug() puts("++++");
    #define gcd(a, b) __gcd(a, b)
    #define lson l,m,rt<<1
    #define rson m+1,r,rt<<1|1
    #define freopenr freopen("in.txt", "r", stdin)
    #define freopenw freopen("out.txt", "w", stdout)
    using namespace std;
    
    typedef long long LL;
    typedef unsigned long long ULL;
    typedef pair<int, int> P;
    const int INF = 0x3f3f3f3f;
    const double inf = 0x3f3f3f3f3f3f;
    const double PI = acos(-1.0);
    const double eps = 1e-5;
    const int maxn = 40000 + 10;
    const int mod = 1000000007;
    const int dr[] = {-1, 0, 1, 0};
    const int dc[] = {0, 1, 0, -1};
    const char *de[] = {"0000", "0001", "0010", "0011", "0100", "0101", "0110", "0111", "1000", "1001", "1010", "1011", "1100", "1101", "1110", "1111"};
    int n, m;
    const int mon[] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
    const int monn[] = {0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
    inline bool is_in(int r, int c){
      return r >= 0 && r < n && c >= 0 && c < m;
    }
    
    struct BigInteger{
      static const int BASE = 100000000;
      static const int WIDTH = 8;
      vector<int> s;
    
      BigInteger(LL num = 0){ *this = num; }
      BigInteger operator = (LL num){
        s.clear();
        do{
          s.push_back(num % BASE);
          num /= BASE;
        } while(num);
        return *this;
      }
      BigInteger operator = (const string &str){
        s.clear();
        int x, len = (str.length() - 1) / WIDTH + 1;
        for(int i = 0; i < len; ++i){
          int end = str.length() - i * WIDTH;
          int start = max(0, end - WIDTH);
          sscanf(str.substr(start, end-start).c_str(), "%d", &x);
          s.push_back(x);
        }
        return *this;
      }
      friend istream &operator >> (istream &in, BigInteger &x){
        string s;
        if(!(in >> s))  return in;
        x = s;
        return in;
      }
    
      string getNum(){
        string ss;
        int t = s.back();
        while(t)  ss.push_back(t % 10 + '0'), t /= 10;
        reverse(ss.begin(), ss.end());
        for(int i = s.size()-2; i >= 0; --i){
          char buf[20];
          sprintf(buf, "%08d", s[i]);
          int len = strlen(buf);
          for(int j = 0; j < len; ++j)  ss.push_back(buf[j]);
          if(ss.size() >= 40)  return ss;
        }
        return ss;
      }
    
      friend ostream &operator << (ostream &out, const BigInteger &x){
        out << x.s.back();
        for(int i = x.s.size()-2; i >= 0; --i){
          char buf[20];
          sprintf(buf, "%08d", x.s[i]);
          int len = strlen(buf);
          for(int j = 0; j < len; ++j)  out << buf[j];
        }
        return out;
      }
    
      BigInteger operator + (const BigInteger &b) const{
        BigInteger c;
        c.s.clear();
        for(int i = 0, g = 0; ; ++i){
          if(!g && i >= s.size() && i >= b.s.size())  break;
          int x = g;
          if(i < s.size())  x += s[i];
          if(i < b.s.size()) x += b.s[i];
            c.s.push_back(x % BASE);
          g = x / BASE;
        }
        return c;
      }
    };
    const int maxnode = 40 * 100000 + 10;
    const int sigam_size = 10;
    struct Tire{
      int ch[maxnode][sigam_size];
      int val[maxnode];
      int sz;
      void init(){
        sz = 1;
        memset(ch, 0, sizeof ch);
        memset(val, 0, sizeof val);
      }
      int idx(char c){ return c - '0'; }
    
      void Insert(const string &s, int v){
        int u = 0;
        for(int i = 0; i < s.size(); ++i){
          int c = idx(s[i]);
          if(!val[u])  val[u] = v;
          if(!ch[u][c])  ch[u][c] = sz++;
          u = ch[u][c];
        }
        if(!val[u])  val[u] = v;
      }
    
      int query(const string &s){
        int u = 0;
        for(int i = 0; i < s.size(); ++i){
          int c = idx(s[i]);
          if(!ch[u][c])  return -1;
          u = ch[u][c];
        }
        return val[u] - 1;
      }
    };
    
    Tire fib;
    
    void init(){
      fib.init();
      BigInteger a = 1;
      BigInteger b = 1;
      BigInteger c = 1;
      fib.Insert(a.getNum(), 1);
      fib.Insert(a.getNum(), 2);
      for(int i = 2; i < 100000; ++i){
        c = a + b;
        string s = c.getNum();
        if(s.size() > 40)  s = s.substr(0, 40);
        fib.Insert(s, i+1);
        a = b;  b = c;
      }
    }
    
    int main(){
      ios::sync_with_stdio(false);
      init();
      int T;  cin >> T;
      for(int kase = 1; kase <= T; ++kase){
        string s;
        cin >> s;
        int ans = fib.query(s);
        cout << "Case #" << kase << ": " << ans << endl;
      }
      return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/dwtfukgv/p/6407916.html
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