Gym

题意：求 n 个哈希值相同的串。

析：直接构造，通过取模来查找相同的串。

代码如下：

#pragma comment(linker, "/STACK:1024000000,1024000000")
#include <cstdio>
#include <string>
#include <cstdlib>
#include <cmath>
#include <iostream>
#include <cstring>
#include <set>
#include <queue>
#include <algorithm>
#include <vector>
#include <map>
#include <cctype>
#include <cmath>
#include <stack>
#include <sstream>
#define debug() puts("++++");
#define gcd(a, b) __gcd(a, b)
#define lson l,m,rt<<1
#define rson m+1,r,rt<<1|1
#define freopenr freopen("in.txt", "r", stdin)
#define freopenw freopen("out.txt", "w", stdout)
using namespace std;

typedef long long LL;
typedef unsigned long long ULL;
typedef pair<int, int> P;
const int INF = 0x3f3f3f3f;
const double inf = 0x3f3f3f3f3f3f;
const double PI = acos(-1.0);
const double eps = 1e-8;
const int maxn = 1e5 + 50;
const LL mod = 2147483648;
const int dr[] = {-1, 0, 1, 0};
const int dc[] = {0, 1, 0, -1};
const char *de[] = {"0000", "0001", "0010", "0011", "0100", "0101", "0110", "0111", "1000", "1001", "1010", "1011", "1100", "1101", "1110", "1111"};
int n, m;
const int mon[] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
const int monn[] = {0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
inline bool is_in(int r, int c){
  return r >= 0 && r < n && c >= 0 && c < m;
}
vector<string> v, ans;

int main(){
  freopen("hash.in", "r", stdin);
  freopen("hash.out", "w", stdout);
  v.push_back("edHs");  v.push_back("fEHs");  v.push_back("edIT");
  for(int i = 0; i < 3; ++i)  for(int j = 0; j < 3; ++j)
  for(int k = 0; k < 3; ++k)  for(int l = 0; l < 3; ++l)
  for(int o = 0; o < 3; ++o)  for(int p = 0; p < 3; ++p)
  for(int q = 0; q < 3; ++q)  ans.push_back("mENAGeS"+v[i]+v[j]+v[k]+v[l]+v[o]+v[p]+v[q]);
  scanf("%d", &n);
  for(int i = 0; i < n; ++i)  cout << ans[i] << endl;
  return 0;
}