Problem:
Given a sorted (in ascending order) integer array nums of n elements and a target value, write a function to search target in nums. If target exists, then return its index, otherwise return -1.
Example 1:
Input: nums = [-1,0,3,5,9,12], target = 9
Output: 4
Explanation: 9 exists in nums and its index is 4
Example 2:
Input: nums = [-1,0,3,5,9,12], target = 2
Output: -1
Explanation: 2 does not exist in nums so return -1
Note:
- You may assume that all elements in nums are unique.
- n will be in the range [1, 10000].
- The value of each element in nums will be in the range [-9999, 9999].
思路:
Solution (C++):
int search(vector<int>& nums, int target) {
int low = 0, high = nums.size()-1;
while (low <= high) {
int mid = low + (high-low) / 2;
if (nums[mid] == target) return mid;
else if (nums[mid] > target) high = mid-1;
else low = mid+1;
}
return -1;
}
性能:
Runtime: 48 ms Memory Usage: 8.8 MB
思路:
Solution (C++):
性能:
Runtime: ms Memory Usage: MB