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  • [Leetcode] Path Sum

    Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.

    For example:
    Given the below binary tree and sum = 22,

                  5
                 / 
                4   8
               /   / 
              11  13  4
             /        
            7    2      1
    

    return true, as there exist a root-to-leaf path 5->4->11->2 which sum is 22.

    水!

     1 /**
     2  * Definition for binary tree
     3  * struct TreeNode {
     4  *     int val;
     5  *     TreeNode *left;
     6  *     TreeNode *right;
     7  *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
     8  * };
     9  */
    10 class Solution {
    11 public:
    12     bool hasPathSum(TreeNode *root, int sum) {
    13         if (root == NULL) {
    14             return false;
    15         }
    16         if (root->left == NULL && root->right == NULL) {
    17             return root->val == sum;
    18         }
    19         bool flag1 = hasPathSum(root->left, sum - root->val);
    20         bool flag2 = hasPathSum(root->right, sum - root->val);
    21         return flag1 || flag2;
    22     }
    23 };
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  • 原文地址:https://www.cnblogs.com/easonliu/p/3634955.html
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