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  • [LeetCode] Merge Intervals

    Given a collection of intervals, merge all overlapping intervals.

    For example,
    Given [1,3],[2,6],[8,10],[15,18],
    return [1,6],[8,10],[15,18].

     1 /**
     2  * Definition for an interval.
     3  * struct Interval {
     4  *     int start;
     5  *     int end;
     6  *     Interval() : start(0), end(0) {}
     7  *     Interval(int s, int e) : start(s), end(e) {}
     8  * };
     9  */
    10  
    11 bool cmp(const Interval &a, const Interval &b) {
    12     return a.start < b.start;
    13 }
    14     
    15 class Solution {
    16 public:
    17     vector<Interval> merge(vector<Interval> &intervals) {
    18         int pos = 0, cnt = 0;
    19         sort(intervals.begin(), intervals.end(), cmp);
    20         for (int i = 1; i < intervals.size(); ++i) {
    21             if (intervals[pos].end >= intervals[i].start) {
    22                     ++cnt;
    23                     if (intervals[pos].end <= intervals[i].end) {
    24                         intervals[pos].end = intervals[i].end;
    25                     }
    26             } else {
    27                 ++pos;
    28                 intervals[pos].start = intervals[i].start;
    29                 intervals[pos].end = intervals[i].end;
    30             }
    31         }
    32         intervals.resize(intervals.size()-cnt);
    33         return intervals;
    34     }
    35 };
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  • 原文地址:https://www.cnblogs.com/easonliu/p/4215802.html
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