Description:
http://acm.pku.edu.cn/JudgeOnline/problem?id=1008
Haab Calendar(365 days per year)
Month1~18: 20 days per month:0~19
pop, no, zip, zotz, tzec, xul, yoxkin, mol, chen, yax, zac, ceh,mac, kankin, muan, pax, koyab, cumhu
Month 19: 5 days per mont: 0~4
Uayet
Tzolkin Calendar(holly year):13个时期，每个时期20daysà 260days per year
used 20 names:imix, ik, akbal, kan, chicchan, cimi, manik, lamat, muluk, ok, chuen, eb, ben,ix, mem, cib, caban, eznab, canac, ahau and 13 numbers; both in cycles
Haab Calendar 、Tzolkin Calendar年份均从0开始
第一天分别为
Haab: 0. pop 0
Tzolkin: 1 imix 0
现在给出一个Haab时间，要求转换为Tzolkin时间
Solution：
将Haab时间转换成从第一天开始的天数，然后转换成Tzolkin时间
1 #include <stdio.h>
2 #include <string.h>
3
4 #define CHARSIZE 16
5
6 // 显然，GCC不允许在定义全局数组时使用const常量来作为数组的大小，用宏却是可以的
7 const int SizeOfMonthTzolkin=20;
8 char monthTzolkinStr[20+1][CHARSIZE]={
9 "","imix", "ik", "akbal", "kan",
10 "chicchan", "cimi", "manik", "lamat",
11 "muluk", "ok", "chuen", "eb",
12 "ben", "ix", "mem", "cib",
13 "caban", "eznab", "canac", "ahau"};
14 const int SizeOfMonthHaab=19;
15 char monthHaabStr[19+1][CHARSIZE] ={
16 "","pop", "no", "zip", "zotz",
17 "tzec", "xul", "yoxkin", "mol",
18 "chen", "yax", "zac", "ceh",
19 "mac", "kankin", "muan", "pax",
20 "koyab", "cumhu", "uayet"};
21
22 int FindHaabMonth(char *inStr)
23 {
24 int i=0;
25
26 for (i=SizeOfMonthHaab; i>1; i--)
27 if (strcmp(inStr,monthHaabStr[i])==0)
28 break;
29 return i;
30 }
31
32 int main ()
33 {
34 int testcase=0;
35 char inStr[CHARSIZE];
36 int totalDays=0,yearHaab=0,dayHaab=0,dayTzolkin=0,yearTzolkin=0;
37 int monthTzolkin=0;
38
39 scanf ("%d", &testcase);
40
41 printf ("%d\n",testcase);
42 while (testcase--)
43 {
44 scanf ("%d.%s%d",&dayHaab,inStr,&yearHaab);
45
46 totalDays = yearHaab*365 + (FindHaabMonth(inStr)-1)*20 + dayHaab+1;
47
48 totalDays --;
49 yearTzolkin = totalDays / 260;
50 totalDays %= 260;
51 monthTzolkin = totalDays % 20 + 1;
52 dayTzolkin = totalDays % 13 + 1;
53 printf ("%d %s %d\n",dayTzolkin,monthTzolkinStr[monthTzolkin],yearTzolkin);
54 }
55 return 0;
56 }