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  • 地图按范围查找-经纬度计算

    C#

    private const double EARTH_RADIUS = 6378.137;//地球半径
            private static double rad(double d)
            {
                return d * Math.PI / 180.0;
            }
    
            public static double GetDistance(double lat1, double lng1, double lat2, double lng2)
            {
                double radLat1 = rad(lat1);
                double radLat2 = rad(lat2);
                double a = radLat1 - radLat2;
                double b = rad(lng1) - rad(lng2);
    
                double s = 2 * Math.Asin(Math.Sqrt(Math.Pow(Math.Sin(a / 2), 2) +
                 Math.Cos(radLat1) * Math.Cos(radLat2) * Math.Pow(Math.Sin(b / 2), 2)));
                s = s * EARTH_RADIUS;
                s = Math.Round(s * 10000) / 10000;
                return s;
            }
    public static double GetShortDistance(double lon1, double lat1, double lon2, double lat2)
            {
                double DEF_PI = 3.14159265359; // PI
                double DEF_2PI = 6.28318530712; // 2*PI
                double DEF_PI180 = 0.01745329252; // PI/180.0
                double DEF_R = 6370693.5; // radius of earth
                double ew1, ns1, ew2, ns2;
                double dx, dy, dew;
                double distance;
    
                // 角度转换为弧度
                ew1 = lon1 * DEF_PI180;
                ns1 = lat1 * DEF_PI180;
                ew2 = lon2 * DEF_PI180;
                ns2 = lat2 * DEF_PI180;
    
                // 经度差
                dew = ew1 - ew2;
                // 若跨东经和西经180 度,进行调整
                if (dew > DEF_PI)
                    dew = DEF_2PI - dew;
                else if (dew < -DEF_PI)
                    dew = DEF_2PI + dew;
                dx = DEF_R * Math.Cos(ns1) * dew;     // 东西方向长度(在纬度圈上的投影长度)
                dy = DEF_R * (ns1 - ns2);             // 南北方向长度(在经度圈上的投影长度)
    
                // 勾股定理求斜边长
                distance = Math.Sqrt(dx * dx + dy * dy);
                return distance;
            }

    SQL

    select id,hotel_code,bname,image,serviceId,fjmoney,score,lon,lat,(2 * 6378.137* ASIN(SQRT(power(SIN(PI()*(28.984223-lat)/360),2)
    +COS(PI()*28.984223/180)* COS(lat * PI()/180)*power(SIN(PI()*(112.92671-lon)/360),2)))) as distance 
     into #temp from hotelid   

    lon 经坐标

    lat 纬坐标

    lat 28.984223
    lon 112.92671

     
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  • 原文地址:https://www.cnblogs.com/elves/p/4143205.html
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