Given an unsorted integer array, find the first missing positive integer.
For example,
Given [1,2,0]
return 3
,
and [3,4,-1,1]
return 2
.
Your algorithm should run in O(n) time and uses constant space.
class Solution {
public:
int firstMissingPositive(int A[], int n)
{
if(n==0) return 1;
for(int i=0;i<n;i++)
if(A[i]!=i+1 && A[i]-1>=0 && A[i]-1<n && A[A[i]-1]!=A[i])
{
int tmp=A[A[i]-1];
A[A[i]-1]=A[i];
A[i]=tmp;
i--;
}
for(int i=0;i<n;i++)
if(A[i]!=i+1) return i+1;
return n+1;
}
};
public:
int firstMissingPositive(int A[], int n)
{
if(n==0) return 1;
for(int i=0;i<n;i++)
if(A[i]!=i+1 && A[i]-1>=0 && A[i]-1<n && A[A[i]-1]!=A[i])
{
int tmp=A[A[i]-1];
A[A[i]-1]=A[i];
A[i]=tmp;
i--;
}
for(int i=0;i<n;i++)
if(A[i]!=i+1) return i+1;
return n+1;
}
};