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  • Search in Rotated Sorted Array II

    Follow up for "Search in Rotated Sorted Array":
    What if duplicates are allowed?

    Would this affect the run-time complexity? How and why?

    Write a function to determine if a given target is in the array.

    class Solution {
    public:
        bool search(int A[], int n, int target) {
            if(n==0return false;
            
            return binary(A,0,n-1,target);
        }
        bool binary(int A[],int x1,int x2,int target)
        {
            if(x1>x2) return false;
            
            int m=(x1+x2)/2;
            if(A[m]==target) return true;
            if(A[x1]<A[x2])
            {
                if(A[m]<target) return binary(A,m+1,x2,target);
                else return binary(A,x1,m-1,target);
            }
            else
            {
                return binary(A,x1,m-1,target) || binary(A,m+1,x2,target);
            }
        }
    }; 
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  • 原文地址:https://www.cnblogs.com/erictanghu/p/3759515.html
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