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  • Candy

    There are N children standing in a line. Each child is assigned a rating value.

    You are giving candies to these children subjected to the following requirements:

    • Each child must have at least one candy.
    • Children with a higher rating get more candies than their neighbors.

    What is the minimum candies you must give?

    class Solution {
    public:
        int candy(vector<int> &ratings) 
        {
            int n=ratings.size();
            if(n<2) return n;
            
            int candys[n];
            for(int i=0;i<n;i++) candys[i]=0;
            
            int cnt=0;
            while(cnt<n)
            {
                for(int i=0;i<n;i++)
                if(candys[i]==0)
                {
                    if((i==0 && (ratings[i+1]>=ratings[i]||candys[i+1]>0)) 
                    || (i==n-1 && (ratings[i-1]>=ratings[i] || candys[i-1]>0)))
                    {
                        if(i==0)
                        {
                            if(ratings[1]==ratings[0]) candys[0]=1;
                            else candys[0]=candys[1]+1;
                        }
                        else
                        {
                            if(ratings[n-1]==ratings[n-2]) candys[n-1]=1;
                            else candys[n-1]=candys[n-2]+1;
                        }
                        cnt++;
                        if(i>0 && candys[i-1]==0) i=i-2;
                        continue;
                    }
                    if(i>0 && i<n-1 && 
                    (candys[i-1]>0 || ratings[i-1]>=ratings[i]) && (candys[i+1]>0  || ratings[i+1]>=ratings[i]))
                    {
                        candys[i]=1;
                        if(ratings[i-1]<ratings[i]) candys[i]=candys[i-1]+1;
                        if(candys[i]<=candys[i+1] && ratings[i+1]<ratings[i])
                            candys[i]=candys[i+1]+1;
                        cnt++;
                        if(i>0 && candys[i-1]==0) i=i-2;
                        continue;
                    }
                }
            }
            int sum=0;
            for(int i=0;i<n;i++) sum=sum+candys[i];
            return sum;
        }
    };
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  • 原文地址:https://www.cnblogs.com/erictanghu/p/3759698.html
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