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  • [Usaco2015 DEC] Counting Haybales

    [题目链接]

             https://www.lydsy.com/JudgeOnline/problem.php?id=4392

    [算法]

             线段树

             时间复杂度 : O(MlogN)

    [代码]

            

    #include<bits/stdc++.h>
    using namespace std;
    #define MAXN 200010
    typedef long long LL;
    
    int n , m;
    LL a[MAXN];
    
    struct SegmentTree
    {
        struct Node
        {
            int l , r;
            LL sum , val;
            LL tag;
        } Tree[MAXN << 2];
        inline void build(int index , int l , int r)
        {
            Tree[index].l = l;
            Tree[index].r = r;
            Tree[index].tag = 0;
            if (l == r)
            {
                Tree[index].sum = Tree[index].val = a[l];
                return;
            }
            int mid = (l + r) >> 1;
            build(index << 1 , l , mid);
            build(index << 1 | 1 , mid + 1 , r);
            update(index);
        }
        inline void update(int index)
        {
            Tree[index].sum = Tree[index << 1].sum + Tree[index << 1 | 1].sum;
            Tree[index].val = min(Tree[index << 1].val , Tree[index << 1 | 1].val);
        }
        inline void pushdown(int index)
        {
            int l = Tree[index].l , r = Tree[index].r;
            int mid = (l + r) >> 1;
            Tree[index << 1].sum += Tree[index].tag * (mid - l + 1);
            Tree[index << 1 | 1].sum += Tree[index].tag * (r - mid);
            Tree[index << 1].val += Tree[index].tag;
            Tree[index << 1 | 1].val += Tree[index].tag;
            Tree[index << 1].tag += Tree[index].tag;
            Tree[index << 1 | 1].tag += Tree[index].tag;
            Tree[index].tag = 0;
        }
        inline void modify(int index , int l , int r , LL value)
        {
            if (Tree[index].l == l && Tree[index].r == r)
            {
                Tree[index].sum += (r - l + 1) * value;
                Tree[index].val += value;
                Tree[index].tag += value;
                return;
            }
            pushdown(index);
            int mid = (Tree[index].l + Tree[index].r) >> 1;
            if (mid >= r) modify(index << 1 , l , r , value);
            else if (mid + 1 <= l) modify(index << 1 | 1 , l , r , value);
            else
            {
                modify(index << 1 , l , mid , value);
                modify(index << 1 | 1 , mid + 1 , r , value);
            }
            update(index);
        }
        inline LL query_sum(int index , int l , int r)
        {
            if (Tree[index].l == l && Tree[index].r == r) return Tree[index].sum;
            pushdown(index);
            int mid = (Tree[index].l + Tree[index].r) >> 1;
            if (mid >= r) return query_sum(index << 1 , l , r);
            else if (mid + 1 <= l) return query_sum(index << 1 | 1 , l , r);
            else return query_sum(index << 1 , l , mid) + query_sum(index << 1 | 1 , mid + 1 , r);
        }
        inline LL query_min(int index , int l , int r)
        {
            if (Tree[index].l == l && Tree[index].r == r) return Tree[index].val;
            pushdown(index);
            int mid = (Tree[index].l + Tree[index].r) >> 1;
            if (mid >= r) return query_min(index << 1 , l , r);
            else if (mid + 1 <= l) return query_min(index << 1 | 1 , l , r);
            else return min(query_min(index << 1 , l , mid) , query_min(index << 1 | 1 , mid + 1 , r));
        }
    } T;
    
    template <typename T> inline void chkmax(T &x , T y) { x = max(x , y); }
    template <typename T> inline void chkmin(T &x , T y) { x = min(x , y); }
    template <typename T> inline void read(T &x)
    {
        T f = 1; x = 0;
        char c = getchar();
        for (; !isdigit(c); c = getchar()) if (c == '-') f = -f;
        for (; isdigit(c); c = getchar()) x = (x << 3) + (x << 1) + c - '0';
        x *= f;
    }
    
    int main()
    {
        
        read(n); read(m);
        for (int i = 1; i <= n; i++) read(a[i]);
        T.build(1 , 1 , n);
        while (m--)
        {
            char op[5];
            scanf("%s",op);
            if (op[0] == 'P')
            {
                int l , r;
                LL x;
                read(l); read(r); read(x);
                T.modify(1 , l , r , x);    
            }
            if (op[0] == 'S')
            {
                int l , r;
                read(l); read(r);
                printf("%lld
    " , T.query_sum(1 , l ,r));
            }
            if (op[0] == 'M')
            {
                int l , r;
                read(l); read(r);
                printf("%lld
    ", T.query_min(1 , l , r));
            }
        }
        
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/evenbao/p/9838641.html
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