学生练习：括号匹配

#include <iostream>
using namespace std;
#define STACKSIZE 10
typedef struct {
	int *base;
	int top;
	int StackSize;
} SqList;
void initStack(SqList *&s)
{
	s=new SqList;
	s->base=new int(STACKSIZE);
	s->top=-1;
	s->StackSize=STACKSIZE;
}
void getTop(SqList *s,char &ch)//获取栈顶元素需要影响实参，故需要加& 
{
	ch= s->base[s->top];
}
void pop(SqList *s,char &ch)
{
	if(s->top==-1)
		return ;
	ch=s->base[s->top--];
}
char push(SqList *s,char ch)
{
	if(s->top==STACKSIZE-1)
		return 0;
	s->base[++s->top]=ch ;
	return 1;
}
int empty(SqList *s)
{
	if(s->top==-1)
		return 1;
	else
		return 0;
}
void matching(char exp[])//在此函数中state表明是否匹配，但并没有输出 
{
	int i=0;
	SqList *s;
	initStack(s);
	int state=1;
	char ch=0;
	while(exp[i]!=''&&state) {
		switch (exp[i]) {
			case '(': {
				push(s,exp[i]);
				i++;
				break;
			}
			case')': {
				if(s->top!=-1) {
					getTop(s,ch);
					if(ch=='(') {
						pop(s,ch);
						i++;
					} else state=0;
				} else state=0;
			}
		}
	}
	if(empty(s) && state)
		cout<<"matching"<<endl;
	else
		cout<<"Not matching"<<endl;
}
int main()
{
	SqList *s;
	char exp[]="(()()";
	//initStack(s);//这个可以不要，因为 matching函数中自己调用了
	matching(exp);
}