Given a binary tree, determine if it is a valid binary search tree (BST).
Assume a BST is defined as follows:
- The left subtree of a node contains only nodes with keys less than the node's key.
- The right subtree of a node contains only nodes with keys greater than the node's key.
- Both the left and right subtrees must also be binary search trees.
Example 1:
2 / 1 3
Binary tree [2,1,3]
, return true.
Example 2:
1 / 2 3
Binary tree [1,2,3]
, return false.
先中序遍历树到数组flag,flag中必定是从小到大排列,如果不是,return false
1 class Solution(object): 2 def isValidBST(self, root): 3 flag = [] 4 self.isv(root,flag) 5 for i in range(1,len(flag)): 6 if flag[i]<=flag[i-1]: 7 return False 8 return True 9 def isv(self,root,flag): 10 if root == None: 11 return 12 self.isv(root.left,flag) 13 flag.append(root.val) 14 self.isv(root.right,flag)