1.jsp，ajax的循环调用，必须要递归，否则会出错。
<%@ page language="java" import="java.util.*" pageEncoding="utf-8"%>
<%@ taglib prefix="s" uri="/struts-tags"%>
<%
String path = request.getContextPath();
String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
%>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<base href="<%=basePath%>">
<title>My JSP 'Scoreinsert.jsp' starting page</title>
<meta http-equiv="pragma" content="no-cache">
<meta http-equiv="cache-control" content="no-cache">
<meta http-equiv="expires" content="0">
<meta http-equiv="keywords" content="keyword1,keyword2,keyword3">
<meta http-equiv="description" content="This is my page">
<script type="text/javascript" src="js/jquery.js"></script>
<!--
<link rel="stylesheet" type="text/css" href="styles.css">
-->
</head>
<script type="text/javascript">
function sub(i)
{
var a = $("table tr").eq(i).children("td").eq(0).children().val();
var b = $("table tr").eq(i).children("td").eq(0).children().eq(1).val();
var c = $("table tr").eq(i).children("td").eq(1).children().val();
var d = $("table tr").eq(i).children("td").eq(2).children().val();
var e = $("table tr").eq(i).children("td").eq(3).children().val();
aja2(a,b,c,d,e,i);
}
function aja2(a,b,c,d,e,i){
$.ajax({
url:'BatchScoreSave.action',
type:'POST', //GET
async:true, //或false,是否异步
data:{
classs:a,
course:b,
number:c,
name:d,
scores:e
},//提交表单数据，也可以直接用data:$('#form').serialize(),
timeout:5000, //超时时间
dataType:'json', //返回的数据格式：json/xml/html/script/jsonp/text
success:function(data){
//console.log(data);
console.log('成功');
if(i<$("table tr").length-1){
i++;
sub(i);
}
},
error:function(xhr,textStatus){
console.log('错误');
},
});
}
</script>
<body>
<s:property value="classs"/>班<s:property value="course"/>成绩录入
<table cellpadding="10" border="1">
<tr>
<th>班级</th>
<th>学号</th>
<th>姓名</th>
<th>成绩</th>
<th>操作</th>
</tr>
<s:iterator value="scorelist">
<tr>
<form action="ScoreSave.action">
<td><input type="text" name="classs" value='<s:property value="id.classs"/>' size="4" readonly="readonly" style="border: 0">
<input type="text" name="score.id.course" value='<s:property value="id.course"/>' style="display:none;"></td>
<td><input type="text" name="score.id.number" value='<s:property value="id.number"/>' size="4" readonly="readonly" style="border: 0"></td>
<td><input type="text" name="score.id.name" value='<s:property value="id.name"/>' size="4" readonly="readonly"style="border: 0"></td>
<td><input type="text" name="score.id.score" value='<s:property value="id.score"/>' size="4"style="border: 0" onkeyup="this.value=this.value.replace(/D/g,'')"></td>
<td><input type="submit" value="保存"></td>
</form>
</tr>
</s:iterator>
</table>
<input type="button" value="提交" onclick="sub(1)">
</body>
</html>
2.action，就是简单的一条数据一条数据的保存，一定有get和set，注意Spring注入不能写get，会报错。
public String BatchScoreSave() throws Exception{
score = new Score();
score.setId(new ScoreId());
score.getId().setClasss(classs);
score.getId().setCourse(course);
score.getId().setNumber(number);
score.getId().setName(name);
score.getId().setScore(scores);
mgr.Scoresave(score);
return SUCCESS;
}
3.struts.xml
<package name="aaa" extends="json-default">
<action name="BatchScoreSave" class="ScoreAction" method="BatchScoreSave"> <result name="success" type="json"> <param name="root"></param> </result></action>
4.结果截图
data:$('#form').serialize(),