#include<iostream>
using namespace std;
class Base
{
public:
virtual void xfn(int i)
{
cout<<"Base::xfn(int i)"<<endl;
}
void yfn(float f)
{
cout<<"Base::yfn(float f)"<<endl;
}
void zfn()
{
cout<<"Base::zfn()"<<endl;
}
};
class Derived:public Base
{
public:
void xfn(int i)
{
cout<<"Derived::xfn(int i)"<<endl;
}
void yfn(int c)
{
cout<<"Derived::yfn(int n)"<<endl;
}
void zfn()
{
cout<<"Derived::zfn()"<<endl;
}
};
void main()
{
Derived d;
Base *pB=&d;
Derived *pD=&d;
pB->xfn (5);
pD->xfn(5);
pB->yfn(3.14f);
pD->yfn(3.14f);
pB->zfn();
pD->zfn();
}
函数的覆盖是发生在派生类和基类之间,两个函数必须完全相同,并且都是虚函数。那么不属于这种情况的就是隐藏了。
运行结果:
Derived::xfn(int i)
Derived::xfn(int i)
Base::yfn(float f)
Derived::yfn(int n)
Base::zfn()
Derived::zfn()
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