题意:
A sequence a0, a1, ..., at - 1 is called increasing if ai - 1 < ai for each i: 0 < i < t.
You are given a sequence b0, b1, ..., bn - 1 and a positive integer d. In each move you may choose one element of the given sequence and add d to it. What is the least number of moves required to make the given sequence increasing?
思路:
n<=2000,直接暴力
代码:
int n,d; ll a[2005]; int main(){ cin>>n>>d; rep(i,1,n) scanf("%I64d",&a[i]); ll ans=0; rep(i,2,n){ if(a[i]>a[i-1]) continue; ll t1=a[i-1]-a[i]; ans+=(t1/d+1); a[i]+=((t1/d+1)*d); } cout<<ans<<endl; return 0; }