zoukankan      html  css  js  c++  java
  • LeetCode 66. Plus One

    分析

    难度 易

    来源

    https://leetcode.com/problems/plus-one/description/

    题目

    Given a non-empty array of digits representing a non-negative integer, plus one to the integer.

    The digits are stored such that the most significant digit is at the head of the list, and each element in the array contain a single digit.

    You may assume the integer does not contain any leading zero, except the number 0 itself.

    Example 1:

    Input: [1,2,3]
    Output: [1,2,4]
    Explanation: The array represents the integer 123.

    Example 2:

    Input: [4,3,2,1]
    Output: [4,3,2,2]
    Explanation: The array represents the integer 4321.
    解答
     1 package LeetCode;
     2 
     3 public class L66_PlusOne {
     4     public int[] plusOne(int[] digits) {
     5         int len=digits.length;
     6         int[] result=new int[len+1];
     7         /*for(int i=0;i<result.length;i++){
     8             System.out.println(result[i]);
     9         }
    10         System.out.println(result);*/
    11         int carry=1;//加1
    12         for(int i=len-1;i>=0;i--){//数组最高位表示数字低位,从最高位开始算
    13             digits[i]+=carry;
    14             if(digits[i]==10){
    15                 digits[i]=0;
    16                 carry=1;//向前进位
    17             }else
    18                 carry=0;
    19         }
    20         if(carry==1){
    21             result[0]=carry;
    22             for(int i=0;i<len;i++){
    23                 result[i+1]=digits[i];
    24             }
    25             return result;
    26         }else
    27             return digits;
    28     }
    29     public static  void main(String[] args){
    30         L66_PlusOne l66=new L66_PlusOne();
    31         int[] digits={9,8,7,6,5,4,3,2,1,0};
    32         int[] result=l66.plusOne(digits);
    33         for(int i=0;i<result.length;i++){
    34             System.out.print(result[i]);
    35         }
    36     }
    37 }

     

    博客园的编辑器没有CSDN的编辑器高大上啊
  • 相关阅读:
    Oracle 11g系列:函数与存储过程
    Oracle 11g系列:视图
    Oracle 11g系列:约束
    Oracle 11g系列:数据表对象
    Oracle 11g系列:数据库
    Oracle 11g系列:SQL Plus与PL/SQL
    Ext.util.TaskRunner定时执行任务
    MS SQL Server存储过程
    UML基础:用例图Use Case Diagram(1)
    UML基础系列:类图
  • 原文地址:https://www.cnblogs.com/flowingfog/p/9808615.html
Copyright © 2011-2022 走看看