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  • kaggle-泰坦尼克号Titanic-2

    下面我们再来看看各种舱级别情况下各性别的获救情况

     1 fig = plt.figure()
     2 fig.set(alpha=0.5)
     3 plt.title(u"根据舱等级和性别的获救情况",fontproperties=getChineseFont())
     4 
     5 ax1 = fig.add_subplot(141)
     6 data_train.Survived[data_train.Sex == 'female'][data_train.Pclass != 3].value_counts().plot(kind='bar', label="female highclass", color='#FA2479')
     7 
     8 ax1.set_xticklabels(['survived','unsurvived'],rotation=0)
     9 ax1.legend(["female/hight_level"], loc='best')
    10 
    11 ax2=fig.add_subplot(142, sharey=ax1)
    12 data_train.Survived[data_train.Sex == 'female'][data_train.Pclass == 3].value_counts().plot(kind='bar', label='female, low class', color='pink')
    13 ax2.set_xticklabels(["unsurvived", "survived"], rotation=0)
    14 plt.legend(["female/low_level"], loc='best')
    15 
    16 ax3=fig.add_subplot(143, sharey=ax1)
    17 data_train.Survived[data_train.Sex == 'male'][data_train.Pclass != 3].value_counts().plot(kind='bar', label='male, high class',color='lightblue')
    18 ax3.set_xticklabels(["unsurvived", "survived"], rotation=0)
    19 plt.legend(["male/hight_level"], loc='best')
    20 
    21 ax4=fig.add_subplot(144, sharey=ax1)
    22 data_train.Survived[data_train.Sex == 'male'][data_train.Pclass == 3].value_counts().plot(kind='bar', label='male low class', color='steelblue')
    23 ax4.set_xticklabels(["unsurvived", "survived"], rotation=0)
    24 plt.legend(["male/low_level"], loc='best')
    25 
    26 plt.show()

    得到下图

    下面再看看大家族对结果有什么影响

    1 g = data_train.groupby(['SibSp','Survived'])
    2 df = pd.DataFrame(g.count()['PassengerId'])
    3 
    4 print(df)

     

     

    PassengerId

    SibSp

    Survived

     

    0

    0

    398

    1

    210

    1

    0

    97

    1

    112

    2

    0

    15

    1

    13

    3

    0

    12

    1

    4

    4

    0

    15

    1

    3

    5

    0

    5

    8

    0

    7

    1 g = data_train.groupby(['Parch','Survived'])
    2 df = pd.DataFrame(g.count()['PassengerId'])
    3 print(df)

    PassengerId

    Parch

    Survived

     

    0

    0

    445

    1

    233

    1

    0

    53

    1

    65

    2

    0

    40

    1

    40

    3

    0

    2

    1

    3

    4

    0

    4

    5

    0

    4

    1

    1

    6

    0

    1

    基本没看出什么特殊关系,暂时作为备选特征。

    ticket是船票编号,应该是unique的,和最后的结果没有太大的关系,不纳入考虑的特征范畴
    cabin只有204个乘客有值,我们先看看它的一个分布

    分布不均匀,应该算作类目型的,本身缺失值就多,还如此不集中,注定很棘手。如果直接按照类目特征处理,太散了,估计每个因子化后的特征都得不到什么权重。加上这么多缺失值,要不先把cabin缺失与否作为条件(虽然这部分信息缺失可能并非未登记,可能只是丢失而已,所以这样做未必妥当)。先在有无cabin信息这个粗粒度上看看Survived的情况。

     1 #cabin的值计数太分散了,绝大多数Cabin值只出现一次。感觉上作为类目,加入特征未必会有效
     2 #那我们一起看看这个值的有无,对于survival的分布状况,影响如何吧
     3 fig = plt.figure()
     4 fig.set(alpha=0.2)  # 设定图表颜色alpha参数
     5 
     6 Survived_cabin = data_train.Survived[pd.notnull(data_train.Cabin)].value_counts()
     7 Survived_nocabin = data_train.Survived[pd.isnull(data_train.Cabin)].value_counts()
     8 df=pd.DataFrame({'Notnull':Survived_cabin, 'null':Survived_nocabin}).transpose()
     9 df.plot(kind='bar', stacked=True)
    10 plt.title(u"按Cabin有无看获救情况",fontproperties=getChineseFont())
    11 plt.xlabel(u"Cabin有无",fontproperties=getChineseFont())
    12 plt.ylabel(u"人数",fontproperties=getChineseFont())
    13 plt.show()
    14 
    15 #似乎有cabin记录的乘客survival比例稍高,那先试试把这个值分为两类,有cabin值/无cabin值,一会儿加到类别特征好了

    似乎有cabin的存活率高一些。

    因此,我们从最明显突出的数据属性开始,cabin和age,有丢失数据对进一步研究影响较大。

    Cabin:暂时按照上面分析的,按Cabin有无数据,将这个属性处理成Ye和No两种类型。

    Age:对于年龄缺失,我们会有以下几种处理方法

    1.如果缺失的样本占总数比例极高,可能就要直接舍弃了,作为特征加入的话,可能导致噪声的产生,影响最终结果。

    2.如果缺失值样本适中,并且该属性非连续值特征属性,那就把NaN作为一个新类别,加到类别特征中。

    3.如果缺失值样本适中,而该属性为连续值特征属性,有时候我们会考虑给定一个step(比如这里的age,可以考虑每隔2/3岁为一个步长),然后把它离散化之后把NaN作为一个type加到属性类目中。

    4.有些情况下,缺失值个数并不多,也可以试着根据已有的值,拟合一下数据补充上。

    本例中,后两种方式应该都是可行的,我们先试着补全。

    我们使用scikit-learn中的RandomForest拟合一下缺失的年龄数据

     1 def set_missing_ages(df):
     2     '''
     3     使用RandomForestClassifier填充缺失的年龄
     4     :param df:
     5     :return:
     6     '''
     7     #把已有的数值型特征取出来丢进Random Forest Regressor中
     8     age_df = df[['Age','Fare','Parch','SibSp','Pclass']]
     9     #乘客分成已知年龄和未知年龄两部分
    10     known_age = age_df[age_df.Age.notnull()].as_matrix()
    11     unknown_age = age_df[age_df.Age.isnull()].as_matrix()
    12 
    13     y = known_age[:,0]#y即目标年龄
    14     X = known_age[:,1:]#X即特征属性值
    15 
    16     rfr = RandomForestRegressor(random_state=0,n_estimators=2000,n_jobs=-1)
    17     rfr.fit(X,y)
    18 
    19     predictedAges = rfr.predict(unknown_age[:,1::])
    20     df.loc[(df.Age.isnull()),'Age'] = predictedAges
    21     return df,rfr
    22 
    23 
    24 def set_Cabin_type(df):
    25     #有客舱信息的为Yes,无客舱信息的为No
    26     df.loc[(df.Cabin.notnull()), 'Cabin'] = "Yes"
    27     df.loc[(df.Cabin.isnull()), 'Cabin'] = "No"
    28     return df
    29 
    30 data_train, rfr = set_missing_ages(data_train)
    31 data_train = set_Cabin_type(data_train)
    32 print(data_train)

     

    PassengerId

    Survived

    Pclass

    Name

    Sex

    Age

    SibSp

    Parch

    Ticket

    Fare

    Cabin

    Embarked

    0

    1

    0

    3

    Braund, Mr. Owen Harris

    male

    22.000000

    1

    0

    A/5 21171

    7.2500

    No

    S

    1

    2

    1

    1

    Cumings, Mrs. John Bradley (Florence Briggs Th...

    female

    38.000000

    1

    0

    PC 17599

    71.2833

    Yes

    C

    2

    3

    1

    3

    Heikkinen, Miss. Laina

    female

    26.000000

    0

    0

    STON/O2. 3101282

    7.9250

    No

    S

    3

    4

    1

    1

    Futrelle, Mrs. Jacques Heath (Lily May Peel)

    female

    35.000000

    1

    0

    113803

    53.1000

    Yes

    S

    4

    5

    0

    3

    Allen, Mr. William Henry

    male

    35.000000

    0

    0

    373450

    8.0500

    No

    S

    5

    6

    0

    3

    Moran, Mr. James

    male

    23.828953

    0

    0

    330877

    8.4583

    No

    Q

    6

    7

    0

    1

    McCarthy, Mr. Timothy J

    male

    54.000000

    0

    0

    17463

    51.8625

    Yes

    S

    7

    8

    0

    3

    Palsson, Master. Gosta Leonard

    male

    2.000000

    3

    1

    349909

    21.0750

    No

    S

    8

    9

    1

    3

    Johnson, Mrs. Oscar W (Elisabeth Vilhelmina Berg)

    female

    27.000000

    0

    2

    347742

    11.1333

    No

    S

    9

    10

    1

    2

    Nasser, Mrs. Nicholas (Adele Achem)

    female

    14.000000

    1

    0

    237736

    30.0708

    No

    C

    10

    11

    1

    3

    Sandstrom, Miss. Marguerite Rut

    female

    4.000000

    1

    1

    PP 9549

    16.7000

    Yes

    S

    11

    12

    1

    1

    Bonnell, Miss. Elizabeth

    female

    58.000000

    0

    0

    113783

    26.5500

    Yes

    S

    12

    13

    0

    3

    Saundercock, Mr. William Henry

    male

    20.000000

    0

    0

    A/5. 2151

    8.0500

    No

    S

    13

    14

    0

    3

    Andersson, Mr. Anders Johan

    male

    39.000000

    1

    5

    347082

    31.2750

    No

    S

    14

    15

    0

    3

    Vestrom, Miss. Hulda Amanda Adolfina

    female

    14.000000

    0

    0

    350406

    7.8542

    No

    S

    15

    16

    1

    2

    Hewlett, Mrs. (Mary D Kingcome)

    female

    55.000000

    0

    0

    248706

    16.0000

    No

    S

    16

    17

    0

    3

    Rice, Master. Eugene

    male

    2.000000

    4

    1

    382652

    29.1250

    No

    Q

    17

    18

    1

    2

    Williams, Mr. Charles Eugene

    male

    32.066493

    0

    0

    244373

    13.0000

    No

    S

    18

    19

    0

    3

    Vander Planke, Mrs. Julius (Emelia Maria Vande...

    female

    31.000000

    1

    0

    345763

    18.0000

    No

    S

    19

    20

    1

    3

    Masselmani, Mrs. Fatima

    female

    29.518205

    0

    0

    2649

    7.2250

    No

    C

    20

    21

    0

    2

    Fynney, Mr. Joseph J

    male

    35.000000

    0

    0

    239865

    26.0000

    No

    S

    21

    22

    1

    2

    Beesley, Mr. Lawrence

    male

    34.000000

    0

    0

    248698

    13.0000

    Yes

    S

    22

    23

    1

    3

    McGowan, Miss. Anna "Annie"

    female

    15.000000

    0

    0

    330923

    8.0292

    No

    Q

    23

    24

    1

    1

    Sloper, Mr. William Thompson

    male

    28.000000

    0

    0

    113788

    35.5000

    Yes

    S

    24

    25

    0

    3

    Palsson, Miss. Torborg Danira

    female

    8.000000

    3

    1

    349909

    21.0750

    No

    S

    25

    26

    1

    3

    Asplund, Mrs. Carl Oscar (Selma Augusta Emilia...

    female

    38.000000

    1

    5

    347077

    31.3875

    No

    S

    26

    27

    0

    3

    Emir, Mr. Farred Chehab

    male

    29.518205

    0

    0

    2631

    7.2250

    No

    C

    27

    28

    0

    1

    Fortune, Mr. Charles Alexander

    male

    19.000000

    3

    2

    19950

    263.0000

    Yes

    S

    28

    29

    1

    3

    O'Dwyer, Miss. Ellen "Nellie"

    female

    22.380113

    0

    0

    330959

    7.8792

    No

    Q

    29

    30

    0

    3

    Todoroff, Mr. Lalio

    male

    27.947206

    0

    0

    349216

    7.8958

    No

    S

    ...

    ...

    ...

    ...

    ...

    ...

    ...

    ...

    ...

    ...

    ...

    ...

    ...

    861

    862

    0

    2

    Giles, Mr. Frederick Edward

    male

    21.000000

    1

    0

    28134

    11.5000

    No

    S

    862

    863

    1

    1

    Swift, Mrs. Frederick Joel (Margaret Welles Ba...

    female

    48.000000

    0

    0

    17466

    25.9292

    Yes

    S

    863

    864

    0

    3

    Sage, Miss. Dorothy Edith "Dolly"

    female

    10.888325

    8

    2

    CA. 2343

    69.5500

    No

    S

    864

    865

    0

    2

    Gill, Mr. John William

    male

    24.000000

    0

    0

    233866

    13.0000

    No

    S

    865

    866

    1

    2

    Bystrom, Mrs. (Karolina)

    female

    42.000000

    0

    0

    236852

    13.0000

    No

    S

    866

    867

    1

    2

    Duran y More, Miss. Asuncion

    female

    27.000000

    1

    0

    SC/PARIS 2149

    13.8583

    No

    C

    867

    868

    0

    1

    Roebling, Mr. Washington Augustus II

    male

    31.000000

    0

    0

    PC 17590

    50.4958

    Yes

    S

    868

    869

    0

    3

    van Melkebeke, Mr. Philemon

    male

    25.977889

    0

    0

    345777

    9.5000

    No

    S

    869

    870

    1

    3

    Johnson, Master. Harold Theodor

    male

    4.000000

    1

    1

    347742

    11.1333

    No

    S

    870

    871

    0

    3

    Balkic, Mr. Cerin

    male

    26.000000

    0

    0

    349248

    7.8958

    No

    S

    871

    872

    1

    1

    Beckwith, Mrs. Richard Leonard (Sallie Monypeny)

    female

    47.000000

    1

    1

    11751

    52.5542

    Yes

    S

    872

    873

    0

    1

    Carlsson, Mr. Frans Olof

    male

    33.000000

    0

    0

    695

    5.0000

    Yes

    S

    873

    874

    0

    3

    Vander Cruyssen, Mr. Victor

    male

    47.000000

    0

    0

    345765

    9.0000

    No

    S

    874

    875

    1

    2

    Abelson, Mrs. Samuel (Hannah Wizosky)

    female

    28.000000

    1

    0

    P/PP 3381

    24.0000

    No

    C

    875

    876

    1

    3

    Najib, Miss. Adele Kiamie "Jane"

    female

    15.000000

    0

    0

    2667

    7.2250

    No

    C

    876

    877

    0

    3

    Gustafsson, Mr. Alfred Ossian

    male

    20.000000

    0

    0

    7534

    9.8458

    No

    S

    877

    878

    0

    3

    Petroff, Mr. Nedelio

    male

    19.000000

    0

    0

    349212

    7.8958

    No

    S

    878

    879

    0

    3

    Laleff, Mr. Kristo

    male

    27.947206

    0

    0

    349217

    7.8958

    No

    S

    879

    880

    1

    1

    Potter, Mrs. Thomas Jr (Lily Alexenia Wilson)

    female

    56.000000

    0

    1

    11767

    83.1583

    Yes

    C

    880

    881

    1

    2

    Shelley, Mrs. William (Imanita Parrish Hall)

    female

    25.000000

    0

    1

    230433

    26.0000

    No

    S

    881

    882

    0

    3

    Markun, Mr. Johann

    male

    33.000000

    0

    0

    349257

    7.8958

    No

    S

    882

    883

    0

    3

    Dahlberg, Miss. Gerda Ulrika

    female

    22.000000

    0

    0

    7552

    10.5167

    No

    S

    883

    884

    0

    2

    Banfield, Mr. Frederick James

    male

    28.000000

    0

    0

    C.A./SOTON 34068

    10.5000

    No

    S

    884

    885

    0

    3

    Sutehall, Mr. Henry Jr

    male

    25.000000

    0

    0

    SOTON/OQ 392076

    7.0500

    No

    S

    885

    886

    0

    3

    Rice, Mrs. William (Margaret Norton)

    female

    39.000000

    0

    5

    382652

    29.1250

    No

    Q

    886

    887

    0

    2

    Montvila, Rev. Juozas

    male

    27.000000

    0

    0

    211536

    13.0000

    No

    S

    887

    888

    1

    1

    Graham, Miss. Margaret Edith

    female

    19.000000

    0

    0

    112053

    30.0000

    Yes

    S

    888

    889

    0

    3

    Johnston, Miss. Catherine Helen "Carrie"

    female

    16.232379

    1

    2

    W./C. 6607

    23.4500

    No

    S

    889

    890

    1

    1

    Behr, Mr. Karl Howell

    male

    26.000000

    0

    0

    111369

    30.0000

    Yes

    C

    890

    891

    0

    3

    Dooley, Mr. Patrick

    male

    32.000000

    0

    0

    370376

    7.7500

    No

    Q

    891 rows × 12 columns

    使用逻辑回归模型时,需要输入的特征都是数值型特征,我们通常会先对类别型特征因子化/one-hot编码。

    例如:

    以Embarked为例,原本一个属性维度,因为其取值是[S,C,Q]中任意一个,将其平展开为 Embarked_C,Embarked_S,Embarked_Q三个属性

    之前Embarked取值为S的,此时的Embarked_S取值为1,而Embarked_C,Embarked_Q则取值为0

    之前Embarked取值为C的,此时的Embarked_C取值为1,而Embarked_S,Embarked_Q则取值为0

    之前Embarked取值为Q的,此时的Embarked_Q取值为1,而Embarked_C,Embarked_S则取值为0

     下面使用pandas的get_dummies来完成这个工作,并拼接在前面的data_train之上,如下所示:

    1 dummies_Cabin = pd.get_dummies(data_train['Cabin'], prefix='Cabin')
    2 dummies_Embarked = pd.get_dummies(data_train['Embarked'], prefix='Embarked')
    3 dummies_Sex = pd.get_dummies(data_train['Sex'], prefix='Sex')
    4 dummies_Pclass = pd.get_dummies(data_train['Pclass'], prefix='Pclass')
    5 df = pd.concat([data_train, dummies_Cabin, dummies_Embarked, dummies_Sex, dummies_Pclass], axis=1)
    6 df.drop(['Pclass', 'Name', 'Sex', 'Ticket', 'Cabin', 'Embarked'], axis=1, inplace=True)
    7 
    8 print(df)

     

    PassengerId

    Survived

    Age

    SibSp

    Parch

    Fare

    Cabin_No

    Cabin_Yes

    Embarked_C

    Embarked_Q

    Embarked_S

    Sex_female

    Sex_male

    Pclass_1

    Pclass_2

    Pclass_3

    0

    1

    0

    22.000000

    1

    0

    7.2500

    1

    0

    0

    0

    1

    0

    1

    0

    0

    1

    1

    2

    1

    38.000000

    1

    0

    71.2833

    0

    1

    1

    0

    0

    1

    0

    1

    0

    0

    2

    3

    1

    26.000000

    0

    0

    7.9250

    1

    0

    0

    0

    1

    1

    0

    0

    0

    1

    3

    4

    1

    35.000000

    1

    0

    53.1000

    0

    1

    0

    0

    1

    1

    0

    1

    0

    0

    4

    5

    0

    35.000000

    0

    0

    8.0500

    1

    0

    0

    0

    1

    0

    1

    0

    0

    1

    5

    6

    0

    23.828953

    0

    0

    8.4583

    1

    0

    0

    1

    0

    0

    1

    0

    0

    1

    6

    7

    0

    54.000000

    0

    0

    51.8625

    0

    1

    0

    0

    1

    0

    1

    1

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    891 rows × 16 columns

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  • 原文地址:https://www.cnblogs.com/freeman818/p/7834178.html
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