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  • python 流程判断

    import getpass
    # print("hello word")

    #
    # name= 'pangxiao'
    # mix_name=name
    # print(mix_name,name)
    # print(2**8)
    # name= "pangxiao"
    # age=26
    # sex=""
    # salary= 3000
    #
    # name=input("name:")
    # age=input("age:")
    # sex=input("sex:")
    # salary=input("salary:")

    # info = """
    # ---------info of
    # name: %s
    # age: %s
    # sex: %s
    # salary: %s
    #
    # """ %(name,age,sex,salary)
    # print(info)

    # info2 = """
    # ---------info2 of
    # name: {_name}
    # age: {_age}
    # sex: {_sex}
    # salary: {_salary}
    #
    # """ .format(_name=name,_age=age,_sex=sex,_salary=salary)
    # print(info2)

    # name3=input("name:")
    # password3=getpass.getpass("password:")
    # print(name3,password3)
    # _name="pangxiao"
    # _password="abc123"
    # name3=input("name:")
    # password3=input("password:")
    # if _name == name3 and _password == password3:
    # print("登录成功!{username}".format(username=name3))
    # else:
    # print("登录失败请重新登录!")
    #自己写的小例子
    dapangxiaozi = 26
    count=5

    while count:
    guess_age = int(input("gusee_age:"))
    if guess_age == dapangxiaozi:
    print("猜对了")
    break
    elif guess_age > dapangxiaozi:
    count -=1
    print("猜高了,再小点!,还有{}次机会".format(count))
    continue
    else:
    count -=1
    print("猜小了,再大点!还有{}次机会".format(count))
    continue
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  • 原文地址:https://www.cnblogs.com/fuyuteng/p/12005121.html
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