1022 作业

写一个基于TCP协议套接字，服务端实现接收客户端的连接并发。

'''服务端'''
import socket
from threading import Thread

s = socket.socket()
s.bind(
    ('127.0.0.1',8848)
)
s.listen(5)
print('等待客户端连接中...')

def server(conn):
    # 将服务端接受收的功能放入多线程调用函数
    while True:
        res = conn.recv(1024)
        print(res.decode('utf-8'))
        if res == 'q':
            break
        conn.send(res.upper())

if __name__ == '__main__':
    while True:
        conn, addr = s.accept()
        print(f'用户{addr}已经连接')
        t = Thread(target=server,args=(conn,))
        # 创建线程
        t.start()

'''客户端'''
import socket
from threading import Thread

c = socket.socket()
c.connect(
    ('127.0.0.1',8848)
)
while True:
    msg = input('请输入发送至服务端消息:').strip()
    if msg == 'q':
        break
    c.send(msg.encode('utf-8'))
    data = c.recv(1024)
    print(data.decode('utf-8'))