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  • MySQL Lock--MySQL加锁学习2

    准备测试数据:

    ## 开启InnoDB Monitor
    SET GLOBAL innodb_status_output=ON;
    SET GLOBAL innodb_status_output_locks=ON;
    
    ## 创建测试表
    DROP TABLE IF EXISTS tb1001;
    
    CREATE TABLE `tb1001` (
      `order_id` INT(11) NOT NULL,
      `order_num` INT(11) DEFAULT NULL,
      `order_type` INT(11) DEFAULT NULL,
      PRIMARY KEY (`order_id`),
      KEY `idx_order_type` (`order_type`)
    ) ENGINE=INNODB DEFAULT CHARSET=utf8;
    
    ## 准备测试数据
    INSERT INTO tb1001(order_id,order_num,order_type)
    VALUES(10,10,10),(20,10,20),(21,10,20),(30,10,30),(40,10,40);
    
    
    ## 查看当前表数据
    SELECT * FROM tb1001;
    +----------+-----------+------------+
    | order_id | order_num | order_type |
    +----------+-----------+------------+
    |       10 |        10 |         10 |
    |       20 |        10 |         20 |
    |       21 |        10 |         20 |
    |       30 |        10 |         30 |
    |       40 |        10 |         40 |
    +----------+-----------+------------+

    测试1:

    ## 先执行事务A
    BEGIN;
    SELECT * FROM tb1001 WHERE order_id=20 FOR UPDATE;
    
    
    ## 再执行事务B
    ## 事务B执行成功,未被阻塞
    BEGIN;
    INSERT INTO tb1001(order_id,order_num,order_type)
    VALUES(19,20,10)

    使用SHOW ENGINE INNODB STATUS 查看,输出锁信息为:

    ---TRANSACTION 1454155, ACTIVE 15 sec
    ## BEGIN;
    ## INSERT INTO tb1001(order_id,order_num,order_type)
    ## VALUES(19,20,10)
    
    1 LOCK struct(s), HEAP size 1136, 0 ROW LOCK(s), UNDO LOG entries 1
    MySQL thread id 1475203, OS thread handle 139581473105664, QUERY id 4426152 127.0.0.1 admin
    TABLE LOCK TABLE `db001`.`tb1001` trx id 1454155 LOCK MODE IX
    
    
    ---TRANSACTION 1454154, ACTIVE 23 sec
    ## SQL
    ## BEGIN;
    ## SELECT * FROM tb1001 WHERE order_id=20 FOR UPDATE;
    
    2 LOCK struct(s), HEAP size 1136, 1 ROW LOCK(s)
    MySQL thread id 1475204, OS thread handle 139581472573184, QUERY id 4426150 127.0.0.1 admin
    TABLE LOCK TABLE `db001`.`tb1001` trx id 1454154 LOCK MODE IX
    RECORD LOCKS SPACE id 29 page NO 3 n bits 80 INDEX PRIMARY of TABLE `db001`.`tb1001` trx id 1454154 lock_mode X LOCKS rec but NOT gap
    Record LOCK, HEAP NO 3 PHYSICAL RECORD: n_fields 5; COMPACT FORMAT; info bits 0
     0: len 4; HEX 80000014; ASC     ;;
     1: len 6; HEX 00000016303e; ASC     0>;;
     2: len 7; HEX f600000032011c; ASC     2  ;;
     3: len 4; HEX 8000000a; ASC     ;;
     4: len 4; HEX 80000014; ASC     ;;

    加锁详解:

    ## SQL
    ## BEGIN;
    ## SELECT * FROM tb1001 WHERE order_id=20 FOR UPDATE;
    
    在可重复读事务隔离级别下,由于 WHERE order_id=20 需要对主键做等值查询,使用加锁规则:
    1、如果找到到满足条件的记录,则对该记录加行锁。
    2、如果未找到满足条件的记录,则对该值前后两条记录之间间隙加间隙锁。
    
    加锁操作如下:
    1、找到满足条件记录order_id=20,对记录order_id=10行锁,锁信息为:
        RECORD LOCKS SPACE id 29 page NO 3 n bits 80 INDEX PRIMARY of TABLE `db001`.`tb1001` trx id 1454154 lock_mode X LOCKS rec but NOT gap
        Record LOCK, HEAP NO 3 PHYSICAL RECORD: n_fields 5; COMPACT FORMAT; info bits 0
        0: len 4; HEX 80000014; ASC     ;; order_id=20
    
    
    ## SQL 
    ## BEGIN;
    ## insert into tb1001(order_id,order_num,order_type)
    ## values(19,20,10)
    
    INSERT加锁规则如下:
    1、INSERT操作会对新插入的记录加行锁(ROW LOCK)+排他锁(X LOCK),不会产生任何GAP锁和Next-Key锁
    2、在插入记录前,会向插入记录所在位置申请意向插入Gap锁(Insertion Intention Gap LOCK),相同区间的意向插入Gap锁不会冲突。
    3、对于唯一索引,如果插入记录时表中已存在相同键值记录(被其他事务修改且未提交),即存在唯一键冲突,会尝试在已有记录上加读锁,然后等待。
    
    加锁操作如下:
    1、对表tb1001做数据插入操作,需要对表tb001上申请意向锁(TABLE LOCK TABLE `db001`.`tb1001` trx id 1454153 LOCK MODE IX)
    2、向新记录order_id=19所在位置申请插入Gap锁(Insertion Intention Gap LOCK),申请成功,
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  • 原文地址:https://www.cnblogs.com/gaogao67/p/11057647.html
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