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  • java——时间复杂度、动态数组

    O(n)不一定小于O(n^2),要具体来看,而我们说的这种时间复杂度其实是渐进时间复杂度,描述的是n趋近于无穷的情况。

    动态数组的时间复杂度:

      添加操作:O(n) addLast()的均摊复杂度为O(1)

      删除操作:O(n)

      修改操作:已知索引:O(1) 未知索引:O(n)

      查找操作:已知索引:O(1) 未知索引:O(n)

    复杂度震荡:removeLast时resize过于着急(Eager)

    解决方案:Lazy

    实现动态数组:

    public class Array<E> {
        //叫它静态数组
        //private int[] data;
        private E[] data;
        private int size;
        //构造函数
        public Array(int capacity) {
            data = (E[])new Object[capacity];
            size = 0;
        }
        //无参数的构造函数,默认数组的容量为10
        public Array() {
            this(10);
        }

        public Array(E[] arr) {
          //java不支持泛型数组:data = new E[];
          data = (E[]) new Object[arr.length];
          for(int i = 0 ; i < arr.length ; i ++)
            data[i] = arr[i];
          size = arr.length;
        }

    public int getSize() {
            return size;
        }
        public int getCapacity() {
            return data.length;
        }
        // O(1)
        public void addLast(E e) {
            add(size, e);
        }
        // O(n)
        public void addFirst(E e) {
            add(0, e);
        }
        // O(n/2) = O(n)
        public void add(int index, E e) {
            if(size>=data.length)
                resize(2 *data.length);
            if(index<0 || index>size)
                throw new IllegalArgumentException("Add failed.index is error.");
            for(int i=size-1;i>=index;i--) {
                data[i+1] = data[i];
            }
            data[index] = e;
            size++;
        }
        @Override
        public String toString() {
            StringBuilder res = new StringBuilder();
            res.append(String.format("Array: size = %d, capacity = %d
    ", size, data.length));
            res.append("[");
            for(int i = 0 ; i<size ; i++) {
                res.append(data[i]);
                if(i != size - 1)
                    res.append(", ");
            }
            res.append("]");
            return res.toString();
        }
        E get(int index) {
            if(index < 0 || index >= size)
                throw new IllegalArgumentException("Get failed. Index is illegal");
            return data[index];
        }
        void set(int index, E e) {
            if(index < 0 || index >= size)
                throw new IllegalArgumentException("Get failed. Index is illegal");
            data[index] = e;
        }
        public boolean contains(E e) {
            for(int i = 0; i < size; i++) {
                if(data[i].equals(e))
                    return true;
            }
            return false;
        }
        public int find(E e) {
            for(int i = 0; i < size; i++) {
                if(data[i].equals(e))
                    return i;
            }
            return -1;
        }
        public E remove(int index) {
            if(index < 0 || index >= size)
                throw new IllegalArgumentException("Get failed. Index is illegal");
            E res = data[index];
            for(int i = index; i<size; i++) {
                data[i] = data[i+1];
            }
            size--;
            //释放空间,也可以不写 
            //loitering objects != memory leak
            data[size] = null;
            if(size == data.length / 4 && data.length / 2 != 0)
                resize(data.length / 2);
            return res;
        }
        public E removeFirst() {
            return remove(0);
        }
        public E removeLast() {
            return remove(size-1);
        }
        //只删除了一个e,并不能保证删除了全部e
        public void removeElement(E e) {
            int index = find(e);
            if(index != -1)
                remove(index);
        }
        private void resize(int newCapacity) {
            E[] newData = (E[]) new Object[newCapacity];
            for(int i=0; i < size; i++) {
                newData[i] = data[i];
            }
            data = newData;
        }
    }
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  • 原文地址:https://www.cnblogs.com/gaoquanquan/p/9788187.html
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