对于Json和对象转换的学习

学习这个的用处有非常多的：

       在传输数据过程中比較查看数据比較清晰，代码也较清晰。也能够避免split函数带来的隐藏bug

当然也有不足：

       准备工具较繁琐，须要准备对象（当然一般项目中每张表都会有相应的Model类，少量数据不建议适用）

------请教各位大侠。能不能直接将Json字符串转换为对象（对象格式无需我们自定义，由于Json中已经非常明白对象的格式了）

介绍两种方式：

第一种：

适用.NET Framework3.5以上版本号的

命名空间为using System.Runtime.Serialization.Json;

        //将一个对象转换为Json字符串
        public static string ObjectToJson_(object obj) 
        {
            DataContractJsonSerializer serializer = new DataContractJsonSerializer(obj.GetType());
            MemoryStream stream = new MemoryStream();
            serializer.WriteObject(stream, obj);
            byte[] dataBytes = new byte[stream.Length];
            stream.Position = 0;
            stream.Read(dataBytes, 0,(int)stream.Length);
            return Encoding.UTF8.GetString(dataBytes);
        }

        //将一个Json字符串转换为对象
        public static object JsonToObject_(string jsonString, Type type)
        {
            DataContractJsonSerializer serilizer = new DataContractJsonSerializer(type);
            MemoryStream stream = new MemoryStream(Encoding.UTF8.GetBytes(jsonString));
            return serilizer.ReadObject(stream);
        }

另外一种：

须要引用Newtonsoft.Json.dll 下载地址

        // 从一个对象信息生成Json串
        public static string ObjectToJson(object obj)
        {
            return JsonConvert.SerializeObject(obj);
        }
        // 从一个Json串生成对象信息
        public static object JsonToObject(string jsonString, Type obj)
        {
            return JsonConvert.DeserializeObject(jsonString, obj);
        }

以下运用的实例：

                    //将提交的数据Json转换为Model
                    string sendMessage = "[{"Type":"精美小炒", "MyLunch":[{"Name":"番茄炒蛋", "Price":"10"}, {"Name":"耗油牛肉", "Price":"14"}, {"Name":"金针菇肥牛", "Price":"16"}, {"Name":"虾仁炒蛋", "Price":"15"}]}, {"Type":"精美套餐", "MyLunch":[{"Name":"商务套餐", "Price":"15"}, {"Name":"红烧猪排套餐", "Price":"12"}, {"Name":"椒盐排条套餐", "Price":"10"}, {"Name":"茄汁牛排套餐", "Price":"10"}]}, {"Type":"特色盖浇饭", "MyLunch":[{"Name":"回锅肉盖浇饭", "Price":"12"}, {"Name":"尖椒牛柳盖浇饭", "Price":"13"}, {"Name":"蒜苗肉丝盖浇饭", "Price":"15"}, {"Name":"辣子鸡盖浇饭", "Price":"12"}]}]";
                    List<Meal> getModel = new List<Meal>();
                    getModel = (List<Meal>)JsonToObject_(sendMessage, typeof(List<Meal>));

                    //将Model转换为Json
                    List<Meal> MealList = new List<Meal>();
                    Meal modelMeal = new Meal();
                    List<Lunch> myLunch = new List<Lunch>();
                    Lunch modelLunch = new Lunch();
                    modelLunch.Name = "台式卤肉";
                    modelLunch.Price = "15";
                    myLunch.Add(modelLunch);
                    modelMeal.MyLunch = myLunch;
                    modelMeal.Type = "星期五套餐";
                    MealList.Add(modelMeal);

                    string jsonString = ObjectToJson_(MealList);
                    result = jsonString;

大概就是这样子了，错误求指正！

QAQ