zoukankan      html  css  js  c++  java
  • A. Dreamoon and Stairs(Codeforces Round #272)

    A. Dreamoon and Stairs
    time limit per test
    1 second
    memory limit per test
    256 megabytes
    input
    standard input
    output
    standard output

    Dreamoon wants to climb up a stair of n steps. He can climb 1 or 2 steps at each move. Dreamoon wants the number of moves to be a multiple of an integer m.

    What is the minimal number of steps making him climb to the top of the stairs that satisfies his condition?

    Input

    The single line contains two space separated integers nm (0 < n ≤ 10000, 1 < m ≤ 10).

    Output

    Print a single integer — the minimal number of moves being a multiple of m. If there is no way he can climb satisfying condition print  - 1instead.

    Sample test(s)
    input
    10 2
    
    output
    6
    
    input
    3 5
    
    output
    -1
    
    Note

    For the first sample, Dreamoon could climb in 6 moves with following sequence of steps: {2, 2, 2, 2, 1, 1}.

    For the second sample, there are only three valid sequence of steps {2, 1}, {1, 2}, {1, 1, 1} with 2, 2, and 3 steps respectively. All these numbers are not multiples of 5.

    找到范围,推断一下全部这个范围的点即可了。

    代码:

    #include <iostream>
    #include <cstdio>
    #include <cstring>
    using namespace std;
    
    int main()
    {
        int n,m;
        int l;
        scanf("%d%d",&n,&m);
        if(n%2==0)
        {
            l=n/2;
        }
        else
        l=n/2+1;
        int ans=-1;
        for(int i=l;i<=n;i++)
        if(i%m==0)
        {
            ans=i;
            break;
        }
        printf("%d
    ",ans);
        return 0;
    }
    


  • 相关阅读:
    第一次练习总结
    第一次上机总结
    写在程序组干活之前
    虚拟机Centos7安装Mysql
    第一章 开发体验
    如何优雅的移植JavaScript组件到Blazor
    Asp.net core中RedisMQ的简单应用
    docker容器安装mysql
    Centos 8安装Docker
    c# 定时启动一个操作、任务(版本2)
  • 原文地址:https://www.cnblogs.com/gcczhongduan/p/5352073.html
Copyright © 2011-2022 走看看