zoukankan      html  css  js  c++  java
  • HDU 3065 病毒侵袭持续中 AC自动机

    HDU 3065

    AC自动机 这个也可以拿来做模板了,使用静态数组模拟建树

      1 //#pragma comment(linker, "/STACK:1677721600")
      2 #include <map>
      3 #include <set>
      4 #include <stack>
      5 #include <queue>
      6 #include <cmath>
      7 #include <ctime>
      8 #include <vector>
      9 #include <cstdio>
     10 #include <cctype>
     11 #include <cstring>
     12 #include <cstdlib>
     13 #include <iostream>
     14 #include <algorithm>
     15 using namespace std;
     16 #define INF 0x3f3f3f3f
     17 #define inf (-((LL)1<<40))
     18 #define lson k<<1, L, (L + R)>>1
     19 #define rson k<<1|1,  ((L + R)>>1) + 1, R
     20 #define mem0(a) memset(a,0,sizeof(a))
     21 #define mem1(a) memset(a,-1,sizeof(a))
     22 #define mem(a, b) memset(a, b, sizeof(a))
     23 #define FIN freopen("in.txt", "r", stdin)
     24 #define FOUT freopen("out.txt", "w", stdout)
     25 #define rep(i, a, b) for(int i = a; i <= b; i ++)
     26 #define dec(i, a, b) for(int i = a; i >= b; i --)
     27 
     28 template<class T> T MAX(T a, T b) { return a > b ? a : b; }
     29 template<class T> T MIN(T a, T b) { return a < b ? a : b; }
     30 template<class T> T GCD(T a, T b) { return b ? GCD(b, a%b) : a; }
     31 template<class T> T LCM(T a, T b) { return a / GCD(a,b) * b;    }
     32 
     33 //typedef __int64 LL;
     34 typedef long long LL;
     35 const int MAXN = 1000 + 100;
     36 const int MAXM = 2000000 + 100;
     37 const double eps = 1e-8;
     38 LL MOD = 1000000007;
     39 
     40 
     41 const int SIGMA_SIZE = 27;
     42 const int MAX_LEN = 52;
     43 
     44 struct ACMachine {
     45     int ch[MAXN * MAX_LEN][SIGMA_SIZE];
     46     int val[MAXN * MAX_LEN];
     47     int fail[MAXN * MAX_LEN];
     48     int last[MAXN * MAX_LEN];
     49 
     50     int id[MAXN * MAX_LEN], ans[MAXN];
     51 
     52     int node_cnt;
     53     queue<int>q;
     54 
     55     void init() {
     56         node_cnt = 0;
     57         mem0(ch); mem0(val);
     58         mem0(fail); mem0(last);
     59         while(!q.empty()) q.pop();
     60     }
     61     int get_idx(char ch) {
     62         if(ch >= 'A' && ch <= 'Z')
     63             return ch - 'A';
     64         return 26;
     65     }
     66     void insert_to_tree(char *str, int p) {
     67         int u = 0, len = strlen(str);
     68         rep (i, 0, len - 1) {
     69             int c = get_idx(str[i]);
     70             if(!ch[u][c]) {
     71                 ch[u][c] = ++node_cnt;
     72             }
     73             u = ch[u][c];
     74         }
     75         val[u] ++;
     76 
     77         id[u] = p;
     78     }
     79     void get_fail() {
     80         rep (c, 0, SIGMA_SIZE - 1) {
     81             int u = ch[0][c];
     82             if(u) q.push(u);
     83         }
     84         while(!q.empty()) {
     85             int r = q.front(); q.pop();
     86             rep (c, 0, SIGMA_SIZE - 1) {
     87                 int u = ch[r][c];
     88                 if(!u) {
     89                     ch[r][c] = ch[fail[r]][c];
     90                     continue;
     91                 }
     92                 q.push(u);
     93                 int v = fail[r];
     94                 while(v && !ch[v][c]) v = fail[v];
     95                 fail[u] = ch[v][c];
     96                 last[u] = val[fail[u]] ? fail[u] : last[fail[u]];
     97             }
     98         }
     99     }
    100     void find_ans(char *str) {
    101 
    102         mem0(ans);
    103 
    104         int len = strlen(str), u = 0;
    105         rep(i, 0, len - 1) {
    106             int c = get_idx(str[i]);
    107             u = ch[u][c];
    108             int v = u;
    109             while(v) {
    110                 if(val[v]) {
    111                     ans[id[u]] ++;
    112                 }
    113                 v = last[v];
    114             }
    115         }
    116 
    117     }
    118 }acm;
    119 
    120 int n;
    121 char str[MAXM], s[MAXN][MAX_LEN];
    122 
    123 int main()
    124 {
    125 //    FIN;
    126     while(~scanf("%d%*c", &n)) {
    127         acm.init();
    128         rep (i, 1, n) {
    129             scanf("%s", s[i]);
    130             acm.insert_to_tree(s[i], i);
    131         }
    132         acm.get_fail();
    133         scanf("%s", str);
    134         acm.find_ans(str);
    135         rep (i, 1, n) if(acm.ans[i]){
    136             printf("%s: %d
    ", s[i], acm.ans[i]);
    137         }
    138     }
    139     return 0;
    140 }
  • 相关阅读:
    推荐一个c++小巧开源且跨平台的图像解码库
    设计模式---桥接模式
    redis数据结构及其使用场景、持久化、缓存淘汰策略
    mysql------explain工具
    mysql索引数据结构
    java8(2)--- Stream API
    java8(1)--- lambda
    springboot自动装配(2)---实现一个自定义自动装配组件
    springboot自动装配(1)---@SpringBootApplication注解怎么自动装配各种组件
    自己挖的坑跪着也要填完---mapper配置文件和java源文件在同一包下
  • 原文地址:https://www.cnblogs.com/gj-Acit/p/4678614.html
Copyright © 2011-2022 走看看