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  • codeforces A. In Search of an Easy Problem

    A. In Search of an Easy Problem
    time limit per test
    1 second
    memory limit per test
    256 megabytes
    input
    standard input
    output
    standard output

    When preparing a tournament, Codeforces coordinators try treir best to make the first problem as easy as possible. This time the coordinator had chosen some problem and asked nn people about their opinions. Each person answered whether this problem is easy or hard.

    If at least one of these nn people has answered that the problem is hard, the coordinator decides to change the problem. For the given responses, check if the problem is easy enough.

    Input

    The first line contains a single integer nn (1n1001≤n≤100) — the number of people who were asked to give their opinions.

    The second line contains nn integers, each integer is either 00 or 11. If ii-th integer is 00, then ii-th person thinks that the problem is easy; if it is 11, then ii-th person thinks that the problem is hard.

    Output

    Print one word: "EASY" if the problem is easy according to all responses, or "HARD" if there is at least one person who thinks the problem is hard.

    You may print every letter in any register: "EASY", "easy", "EaSY" and "eAsY" all will be processed correctly.

    Examples
    input
    Copy
    3
    0 0 1
    output
    Copy
    HARD
    input
    Copy
    1
    0
    output
    Copy
    EASY

    为了熟悉CF。忍了。。
    #include<iostream>
    #include<cstdlib>
    using namespace std;
    
    int main(){
        int n;
        char* hard= "HARD";
        char* easy= "EASY";
        cin>>n;
        for(int i=0;i<n;i++){
            int c;
            cin>>c;
            if(c==1){
                cout<<hard;
                exit(0);
            }
        }
        cout<<easy;
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/godoforange/p/10944370.html
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