Can you solve this equation?
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 5667 Accepted Submission(s): 2681
http://acm.hdu.edu.cn/showproblem.php?pid=2199
Problem Description
Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y,can you find its solution between 0 and 100;
Now please try your lucky.
Now please try your lucky.
Input
The first line of the input contains an integer T(1<=T<=100) which means the number of test cases. Then T lines follow, each line has a real number Y (fabs(Y) <= 1e10);
Output
For each test case, you should just output one real number(accurate up to 4 decimal places),which is the solution of the equation,or “No solution!”,if there is no solution for the equation between 0 and 100.
Sample Input
2 100 -4
Sample Output
1.6152 No solution!
Author
Redow
Recommend
lcy
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代码:
#include<iostream> #include<cstdio> #define sum(x) ((8*x*x*x*x)+(7*x*x*x)+(2*x*x)+(3*x)+(6)) using namespace std; int main() { int t; double y,mid,left,right; cin>>t; while(t--) { scanf("%lf",&y); left=0.0,right=100.0; if(y>=6.0&&y<=sum(100)) { while(right-left>1e-8) { mid=(left+right)/2.0; if(sum(mid)-y>1e-8) right=mid; else if(y-sum(mid)>1e-8) left=mid; else break; } printf("%.4lf ",mid); } else puts("No solution!"); } return 0; }