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  • Shell命令_for



    chmod 755 demo.sh
    ./demo.sh
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    #!/bin/bash
    # Author:James 2016-10-15
     
    # 集合以空格分割
    for  i in 1 2 3 4 5 6
        do
            echo "$i"
        done
     
     

     


    #!/bin/bash
    # Author:James 2016-10-15
    # 批量压缩脚本
     
    cd /tmp/shs
    #所有sh文件覆盖到sh.log文件
    ls *.sh > sh.log
    for i in $(cat sh.log)
        do
            #tar -zxf $i &>/dev/null
            echo "File Name is $i"
        done
    rm -rf /tmp/shs/sh.log
     

     


     
    #!/bin/bash
    # Author:James 2016-10-15
    # 计算1..100之和
     
    sum=0
    for(( i=1;i<=100;i++ ))
            do
                    #echo "$i"
                    sum=$(( $sum+$i ))
            done
    echo "sum is:$sum"
     
     
     

     


    #!/bin/bash
    # Author:James 2016-10-15
    # 批量添加用户和默认密码
     
    #等待30秒输入name
    read -t 30 -p "input name:" name
    read -t 30 -p "input password:" pass
    read -t 30 -p "input number:" num
     
    # 输入的name,pass,num都不是控制
    if [ ! -z "$name" -a ! -z "$pass" -a ! -z "$num" ]
            then
                    # 将num变量以数字开头的结尾的字符改为空字符串
                    y=$(echo $num | sed 's/^[0-9]*$'//g)
                    #变量y为空,表示num变量都是数字
                    if [ -z "$y" ]
                            then
                                    for(( i=1;i<=$num;i++ ))
                                            do
                                                    #批量添加用户
                                                    /usr/sbin/useradd "$name$i" &>/dev/null
                                                    #批量赋予默认密码
                                                    echo $pass | /usr/bin/passwd --stdin "&name$i" &>/dev/null
                                            done
                    fi
    fi
     
    # 使用cat /etc/passwd 查看用户是否增加成功





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  • 原文地址:https://www.cnblogs.com/gossip/p/5962986.html
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