1 class At{ 2 string state="start"; 3 unordered_map<string,vector<string>>table={ 4 {"start",{"start","signed","in_number","end"}}, 5 {"in_number",{"end","end","in_number","end"}}, 6 {"signed",{"end","end","in_number","end"}}, 7 {"end",{"end","end","end","end"}} 8 };//状态转换图 9 int get_c(char c){ 10 if(c==' '){ 11 return 0; 12 }else if(c=='+'||c=='-'){ 13 return 1; 14 }else if(c>='0'&&c<='9'){ 15 return 2; 16 } 17 return 3; 18 }//分别对应空格,加减,数字,其他 19 public: 20 int sign=1; 21 long long ans=0; 22 void get(char c){ 23 state=table[state][get_c(c)]; 24 if(state=="signed"){ 25 sign=c=='+'? 1:-1; 26 }else if(state=="in_number"){ 27 ans=ans*10+c-'0'; 28 ans=sign==1?min(ans,(long long)INT_MAX):min(ans,-(long long)INT_MIN);//注意点INT_MAX!=-INT_MIN 29 } 30 } 31 }; 32 class Solution { 33 public: 34 int myAtoi(string str) { 35 At at; 36 for(auto x:str){ 37 at.get(x); 38 } 39 return at.sign*at.ans; 40 } 41 };