zoukankan      html  css  js  c++  java
  • 682. Baseball Game

    题目描述:

    You're now a baseball game point recorder.

    Given a list of strings, each string can be one of the 4 following types:

    1. Integer (one round's score): Directly represents the number of points you get in this round.
    2. "+" (one round's score): Represents that the points you get in this round are the sum of the last two valid round's points.
    3. "D" (one round's score): Represents that the points you get in this round are the doubled data of the last valid round's points.
    4. "C" (an operation, which isn't a round's score): Represents the last valid round's points you get were invalid and should be removed.

    Each round's operation is permanent and could have an impact on the round before and the round after.

    You need to return the sum of the points you could get in all the rounds.

    Example 1:

    Input: ["5","2","C","D","+"]
    Output: 30
    Explanation: 
    Round 1: You could get 5 points. The sum is: 5.
    Round 2: You could get 2 points. The sum is: 7.
    Operation 1: The round 2's data was invalid. The sum is: 5.  
    Round 3: You could get 10 points (the round 2's data has been removed). The sum is: 15.
    Round 4: You could get 5 + 10 = 15 points. The sum is: 30.
    

    Example 2:

    Input: ["5","-2","4","C","D","9","+","+"]
    Output: 27
    Explanation: 
    Round 1: You could get 5 points. The sum is: 5.
    Round 2: You could get -2 points. The sum is: 3.
    Round 3: You could get 4 points. The sum is: 7.
    Operation 1: The round 3's data is invalid. The sum is: 3.  
    Round 4: You could get -4 points (the round 3's data has been removed). The sum is: -1.
    Round 5: You could get 9 points. The sum is: 8.
    Round 6: You could get -4 + 9 = 5 points. The sum is 13.
    Round 7: You could get 9 + 5 = 14 points. The sum is 27.
    

    Note:

    • The size of the input list will be between 1 and 1000.
    • Every integer represented in the list will be between -30000 and 30000.

    解题思路:

    使用stack记录每轮得分。

    代码:

     1 class Solution {
     2 public:
     3     int calPoints(vector<string>& ops) {
     4         stack<int> nums;
     5         int sum = 0;
     6         for (auto str : ops) {
     7             if (str == "C") {
     8                 int num = nums.top();
     9                 nums.pop();
    10                 sum -= num;
    11             } else if (str == "D") {
    12                 int num = nums.top();
    13                 nums.push(2*num);
    14                 sum += 2*num;
    15             } else if (str == "+") {
    16                 int num1 = nums.top();
    17                 nums.pop();
    18                 int num2 = nums.top();
    19                 nums.push(num1);
    20                 nums.push(num1 + num2);
    21                 sum = sum + num1 + num2;
    22             } else {
    23                 int num = stoi(str);
    24                 nums.push(num);
    25                 sum += num;
    26             }
    27         }
    28         return sum;
    29     }
    30 };
  • 相关阅读:
    Mysql注入绕过姿势
    轻松入侵我学校网站
    华科机考:矩阵转置
    浙大patB习题的一点总结
    链表的一些基本操作
    关于C中函数传参的一点理解
    Java与JavaScript中判断两字符串是否相等的区别
    Jsp中out.println()与System.out.println()的区别
    eclipse背景主题
    Kruskal算法的简单实现
  • 原文地址:https://www.cnblogs.com/gsz-/p/9483417.html
Copyright © 2011-2022 走看看