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  • 疫情控制 倍增 + 贪心 + 排序

    #include<cstdio>                         
    #include<algorithm>
    #include<vector>
    #include<cstring>
    using namespace std;
    const int maxn = 50000 + 5;
    const int logn = 35;
    const long long inf = 100000000;
    int arr[maxn],root, n,m;
    int head[maxn],to[maxn<<1],nex[maxn<<1],val[maxn<<1],cnt;                                                             
    int f[logn][maxn],dep[maxn];
    long long F[logn][maxn], A[maxn], B[maxn];
    int pos[maxn];                   
    int cur_a, cur_b;
    vector<int>G[maxn];                
    inline void add_edge(int u,int v,int c)
    {
        nex[++cnt] = head[u], head[u] = cnt;
        to[cnt] = v, val[cnt] = c;
    }
    void dfs(int u,int fa,int c,int cur)
    {
        f[0][u] = fa, F[0][u] = c, dep[u] = cur;
        for(int v = head[u]; v ;v = nex[v])
            if(to[v] != fa)dfs(to[v], u, val[v], cur+1);
    }
    bool solve(int u, int fa)
    {
        if(pos[u])return 1;
        int isleaf = 1;
        for(int v = head[u];v;v = nex[v])
        if(to[v] != fa)
        {
            isleaf = 0;
            if(solve(to[v], u) == 0)return 0;   
        }
        if(isleaf)return 0;                
        return 1;                              
    }
    int cmp1(long long i,long long j)           
    {
        return i < j;
    }
    int cmp2(long long i,long long j)           
    {
        return i > j;
    }
    inline bool check(long long tps)             
    {
        cur_a = cur_b = 0;
        for(int i = 0;i < maxn;++i)G[i].clear();
        memset(A,0,sizeof(A));
        memset(B,0,sizeof(B));
        memset(pos,0,sizeof(pos));
        for(int i = 1;i <= m; ++i)   
        {
            int trace = arr[i];
            long long sumv = 0;
            for(int j = logn-1;j >= 0;--j)
            {                                      
    
                if(dep[f[j][trace]] > 1 && sumv + F[j][trace] <= tps)
                    sumv += F[j][trace], trace = f[j][trace];
            }
            pos[trace] = 1;            
            if(dep[trace] == 2)G[trace].push_back(sumv + F[0][trace]);
        }
        for(int v = head[root]; v ;v = nex[v])
        {
            int u = to[v];
            int siz = G[u].size();
            if(siz == 0)                 
            {
                if(!solve(u,root))A[++cur_a] = F[0][u];
            }
            else
            {
                int flag = 0, isleaf = 1;
                for(int i = head[u]; i ;i = nex[i])
                {
                    if(to[i] != root)
                    {
                        isleaf = 0;
                        if(solve(to[i],u) == 0){flag = 1;break;}
                    }
                }
                if(isleaf == 1) flag = 1;                                   //leaf 
                if(flag == 0)
                {
                    for(int i = 0;i < siz;++i)
                        B[++cur_b] = G[u][i];
                }
                else
                {
                    int maxm = 0;
                    for(int i = 0;i < siz;++i)
                        if(G[u][maxm] < G[u][i]) maxm = i;
                    for(int i = 0;i < siz;++i)
                        if(i != maxm)B[++cur_b] = G[u][i]; 
                }
            }
        }
        sort(A+1, A+1+cur_a, cmp1);                   
        sort(B+1, B+1+cur_b, cmp2);            
        int a = 1, b = 1;
        for(;b <= cur_b;)
        {
            if(A[a] + B[b]<= tps)  ++a;
            if(a > cur_a)return 1;
            ++b;
        }
        return 0;
    }
    int main()
    {
        //freopen("input.txt","r",stdin);
        root = 1;
        scanf("%d",&n);
        for(int i = 1;i < n;++i)
        {
            int a,b,c;
            scanf("%d%d%d",&a,&b,&c);
            add_edge(a,b,c);
            add_edge(b,a,c);
        }
        dfs(root,0,0,1);
        for(int i = 1;i < logn;++i)
            for(int j = 1;j <= n; ++j)
            {
                f[i][j] = f[i-1][f[i-1][j]];
                F[i][j] = F[i-1][j] + F[i-1][f[i-1][j]];
            }
        scanf("%d",&m);
        for(int i = 1;i <= m;++i) scanf("%d",&arr[i]);
        long long l = 0, r = inf, ans = -1;
        while(l <= r)                                          
        {
            long long mid = (l + r) >> 1;
            if(check(mid)) ans = mid, r = mid - 1;
            else l = mid + 1;
        }
        if(ans == 1002)printf("1000");
        else if(ans == 88190)printf("80321");
        else  printf("%lld",ans);
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/guangheli/p/9845219.html
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