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  • LeetCode第四天

    leetcode 第四天

    2018年1月4日

    15.(628)Maximum Product of Three Numbers

    JAVA
    class Solution {
        public int maximumProduct(int[] nums) {
            Arrays.sort(nums);
            return (nums[0]*nums[1]*nums[nums.length-1])>(nums[nums.length-1]*nums[nums.length-2]*nums[nums.length-3])?(nums[0]*nums[1]*nums[nums.length-1]):(nums[nums.length-1]*nums[nums.length-2]*nums[nums.length-3]);
        }
    }
    

    16.(628)Maximum Product of Three Numbers

    JAVA
    class Solution {
        public int thirdMax(int[] nums) {
            Integer first = null ,second = null,third = null;
            for(Integer n : nums){
                if(n.equals(first)||n.equals(second)||n.equals(third)) continue;
                if(first==null||n>first){
                    third = second;
                    second = first;
                    first = n;
                }else if(second == null||n>second){
                    third = second;
                    second = n;
                }else if(third == null||n>third){
                    third = n;
                }
        
            }
            
            return third == null?first:third;
        }
            
    }
    

    17.(643) Maximum Average Subarray I

    JAVA
    class Solution {
        public double findMaxAverage(int[] nums, int k) {
            double window = 0;
            double maxAvg = 0;
            for(int i =0;i<k;i++){
                window +=nums[i];
                maxAvg = window;
            }
                
            for(int i = k;i<nums.length;i++){
                window = window+nums[i]-nums[i-k];
                maxAvg = Math.max(maxAvg,window);
            
            }
                
                
            return maxAvg/k;
        }
    }
    

    18.(448) Find All Numbers Disappeared in an Array

    JAVA
    class Solution {
        public List<Integer> findDisappearedNumbers(int[] nums) {
            List<Integer> result = new ArrayList<Integer>();
            for(int i =0;i<nums.length;i++){
                
                nums[Math.abs(nums[i])-1] = -1 * Math.abs(nums[Math.abs(nums[i])-1]); 
            }
            for(int i =0;i<nums.length;i++){
                if(nums[i]>0)
                    result.add(i+1);
            }
            return result;
        }
    }
    

    19.(485) Max Consecutive Ones

    JAVA
    class Solution {
        public int findMaxConsecutiveOnes(int[] nums) {
            int max = 0;
            int times = 0;
            for(int i =0;i<nums.length;i++){
                if(nums[i]==1){
                    times++;
                    max = Math.max(max,times);
                }else{
                    times = 0;
                }
            }
            return max;
        }
    }
    

    20.(88) Merge Sorted Array

    JAVA
    class Solution {
        public void merge(int[] nums1, int m, int[] nums2, int n) {
            while(n > 0){
                if(m>0)
                    nums1[n+m-1] = nums1[m-1]>nums2[n-1]?nums1[--m]:nums2[--n];
                else
                    nums1[n-1] = nums2[--n];
            }
        }
    }
    

    21.(605) Can Place Flowers

    JAVA
    class Solution {
        public boolean canPlaceFlowers(int[] flowerbed, int n) {
            int count = 0;
            for(int i =0;i<flowerbed.length;i++){
                if(flowerbed[i]==0&&(i==0||flowerbed[i-1]==0)&&(i==flowerbed.length-1||flowerbed[i+1]==0)){
                    count++;
                    flowerbed[i]=1;
                    if(count==n)
                        return true;
                }
            }
            return count >= n;
        }
    }
    
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  • 原文地址:https://www.cnblogs.com/guoyaohua/p/8196716.html
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