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  • 24、获取所有非manager员工当前的薪水情况

    1、题目描述

    获取所有非manager员工当前的薪水情况,给出dept_no、emp_no以及salary ,当前表示to_date='9999-01-01'
    CREATE TABLE `dept_emp` (
    `emp_no` int(11) NOT NULL,
    `dept_no` char(4) NOT NULL,
    `from_date` date NOT NULL,
    `to_date` date NOT NULL,
    PRIMARY KEY (`emp_no`,`dept_no`));
    CREATE TABLE `dept_manager` (
    `dept_no` char(4) NOT NULL,
    `emp_no` int(11) NOT NULL,
    `from_date` date NOT NULL,
    `to_date` date NOT NULL,
    PRIMARY KEY (`emp_no`,`dept_no`));
    CREATE TABLE `employees` (
    `emp_no` int(11) NOT NULL,
    `birth_date` date NOT NULL,
    `first_name` varchar(14) NOT NULL,
    `last_name` varchar(16) NOT NULL,
    `gender` char(1) NOT NULL,
    `hire_date` date NOT NULL,
    PRIMARY KEY (`emp_no`));
    CREATE TABLE `salaries` (
    `emp_no` int(11) NOT NULL,
    `salary` int(11) NOT NULL,
    `from_date` date NOT NULL,
    `to_date` date NOT NULL,
    PRIMARY KEY (`emp_no`,`from_date`));

    输入描述:

    输出描述:

    dept_noemp_nosalary
    d001 10001 88958
    d004 10003 43311
    d005 10007 88070
    d006 10009 95409


    2、代码

    select t1.dept_no,t1.emp_no,s.salary
    from (
    select d.dept_no,d.emp_no,d.from_date,d.to_date
    from dept_emp d
    where d.emp_no not in
    (select m.emp_no 
     from dept_manager m 
     where m.to_date='9999-01-01')
    ) t1  inner join salaries s 
    on t1.emp_no=s.emp_no and t1.to_date='9999-01-01' and s.to_date='9999-01-01';
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  • 原文地址:https://www.cnblogs.com/guoyu1/p/12705965.html
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