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  • 26、汇总各个部门当前员工的title类型的分配数目

    1、题目描述

    汇总各个部门当前员工的title类型的分配数目,结果给出部门编号dept_no、dept_name、其当前员工所有的title以及该类型title对应的数目count
    CREATE TABLE `departments` (
    `dept_no` char(4) NOT NULL,
    `dept_name` varchar(40) NOT NULL,
    PRIMARY KEY (`dept_no`));
    CREATE TABLE `dept_emp` (
    `emp_no` int(11) NOT NULL,
    `dept_no` char(4) NOT NULL,
    `from_date` date NOT NULL,
    `to_date` date NOT NULL,
    PRIMARY KEY (`emp_no`,`dept_no`));
    CREATE TABLE IF NOT EXISTS `titles` (
    `emp_no` int(11) NOT NULL,
    `title` varchar(50) NOT NULL,
    `from_date` date NOT NULL,
    `to_date` date DEFAULT NULL);

    输入描述:

    输出描述:

    dept_nodept_nametitlecount
    d001 Marketing Senior Engineer 1
    d001 Marketing Staff 1
    d002 Finance Senior Engineer 1
    d003 Human Resources Senior Staff 1
    d004 Production Senior Engineer 2
    d005 Development Senior Staff 1
    d006 Quality Management Engineer 2
    d006 Quality Management Senior Engineer

    2、代码:

    select t1.dept_no,dp.dept_name,t1.title,t1.count
    from (
    select d.emp_no,d.dept_no,t.title,count(1) as count
    from dept_emp d 
    inner join titles t on d.emp_no=t.emp_no and d.to_date='9999-01-01' and t.to_date='9999-01-01'
    group by d.dept_no,t.title ) t1
    inner join departments dp
    on t1.dept_no=dp.dept_no ;
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  • 原文地址:https://www.cnblogs.com/guoyu1/p/12706706.html
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