• 【NOI OpenJudge】【1.4】编程基础之逻辑表达式与条件分支


    在这里插入图片描述

    01:判断数正负

    #include<cstdio>
    #include<iostream>
    using namespace std;
    int main(){
        int n;  cin>>n;
        if(n > 0){
            printf("positive
    ");
        }else if(n == 0){
            printf("zero
    ");
        }else{
            printf("negative
    ");
        }
        return 0;
    }
    

    02:输出绝对值

    #include<cstdio>
    #include<iostream>
    using namespace std;
    int main(){
        float x;
        cin>>x;
        if(x>=0)printf("%.2f",x);
        else printf("%.2f",-x);
        return 0;
    }
    

    03:奇偶数判断

    #include<cstdio>
    #include<iostream>
    using namespace std;
    int main(){
        int x;
        cin>>x;
        if(x%2==1)printf("odd");
        else printf("even");
        return 0;
    }
    

    04:奇偶ASCII值判断

    #include<cstdio>
    #include<iostream>
    using namespace std;
    int main(){
        char c;
        scanf("%c",&c);
        if((int)c%2==1)cout<<"YES";
        else cout<<"NO";
        return 0;
    }
    

    05:整数大小比较

    #include<cstdio>
    #include<iostream>
    using namespace std;
    int main(){
        int a, b;
        cin>>a>>b;
        if(a > b)cout<<">";
        else if(a==b)cout<<"=";
        else cout<<"<";
        return 0;
    }
    

    06:判断是否为两位数

    #include<iostream>
    using namespace std;
    int main(){
        int n; 
        cin>>n;
        if(n >= 10 && n <= 99){
            cout<<1;
        }else {
            cout<<0<<'
    ';
        }
        return 0;
    }
    

    07:收集瓶盖赢大奖

    #include<iostream>
    using namespace std;
    int main(){
        int a, b;
        cin>>a>>b;
        if(a >= 10 || b >= 20){
            cout<<1<<'
    ';
        }else cout<<0;
        return 0;
    }
    

    08:判断一个数能否同时被3和5整除

    #include<iostream>
    using namespace std;
    int main(){
        int n;  cin>>n;
        if(n%3==0 && n%5==0)cout<<"YES";
        else cout<<"NO";
        return 0;
    }
    

    09:判断能否被3,5,7整除

    #include<iostream>
    using namespace std;
    int main(){
        int n;  cin>>n;
        int ok = 0;
        if(n%3==0){
            cout<<3<<' '; ok = 1;
        }
        if(n%5==0){
            cout<<5<<' '; ok = 1;
        }
        if(n%7==0){
            cout<<7<<' '; ok = 1;
        }
        if(!ok)cout<<"n";
        return 0;
    }
    

    10:有一门课不及格的学生

    #include<iostream>
    using namespace std;
    int main(){
        int a, b;
        cin>>a>>b;
        if(a<60 && b>=60 || b<60&&a>=60){
            cout<<1;
        }else cout<<0;
        return 0;
    }
    

    11:晶晶赴约会

    #include<iostream>
    using namespace std;
    int main(){
        int n;
        cin>>n;
        if(n==1 || n==3 || n==5){
            cout<<"NO";
        }else cout<<"YES";
        return 0;
    }
    

    12:骑车与走路

    #include<iostream>
    using namespace std;
    int main(){
        int d;  cin>>d;
        int bt = d/3+27+23;
        int wt = d/1.2;
        if(bt < wt){cout<<"Bike";return 0;}
        if(bt > wt){cout<<"Walk";return 0;}
        cout<<"All";
        return 0;
    }
    

    13:分段函数

    #include<cstdio>
    #include<iostream>
    using namespace std;
    int main(){
        float x, y;  cin>>x;
        if(x < 5)y = -x+2.5;
        else if(x < 10)y = 2-1.5*(x-3)*(x-3);
        else if(x < 20)y = y=x/2-1.5;
        printf("%.3f",y);
        return 0;
    }
    

    14:计算邮资

    #include<cstdio>
    #include<iostream>
    using namespace std;
    int main(){
        int w; char s;
        cin>>w>>s;
        int ans = 8;
        if(s=='y')ans += 5;
        if(w<=1000){
            cout<<ans<<'
    ';
            return 0;
        }else{
            w -= 1000;
            ans += ((w-1)/500+1)*4;
            cout<<ans;
        }
        return 0;
    }
    
    

    15:最大数输出

    #include<iostream>
    #include<cmath>
    using namespace std;
    int main(){
        int a, b, c;
        cin>>a>>b>>c;
        cout<<(max(a,max(b,c)))<<'
    ';
        return 0;
    }
    

    16:三角形判断

    #include<bits/stdc++.h>
    using namespace std;
    int main(){
        int a[3];
        cin>>a[0]>>a[1]>>a[2];
        sort(a,a+3);
        if(a[2]<a[1]+a[0]&&a[0]>a[2]-a[1]){
            cout<<"yes";
        }
        else cout<<"no";
        return 0;
    }
    

    17:判断闰年

    #include<iostream>
    #include<cmath>
    using namespace std;
    int main(){
        int y;  cin>>y;
        if(y%4==0&&y%100!=0 || y%100==0&&y%400==0)cout<<"Y";
        else cout<<"N";
        return 0;
    }
    

    18:点和正方形的关系

    #include<iostream>
    #include<cmath>
    using namespace std;
    int main(){
        int x, y;
        cin>>x>>y;
        if(x<=1&&x>=-1&&y<=1&&y>=-1)cout<<"yes";
        else cout<<"no";
        return 0;
    }
    

    19:简单计算器

    #include<iostream>
    #include<cmath>
    using namespace std;
    int main(){
        int a, b; char op;
        cin>>a>>b>>op;
        if(op == '+')cout<<(a+b);
        else if(op=='-')cout<<(a-b);
        else if(op=='*')cout<<(a*b);
        else if(op=='/'){
            if(b==0)cout<<"Divided by zero!";
            else cout<<(a/b);
        }else cout<<"Invalid operator!";
        return 0;
    }
    

    20:求一元二次方程的根

    #include<cstdio>
    #include<iostream>
    #include<cmath>
    using namespace std;
    int main(){
        float a, b, c, x;
        cin>>a>>b>>c;
        if(b*b==4*a*c){
            printf("x1=x2=%.5f",(-b+sqrt(b*b-4*a*c))/(2*a));
        }else if(b*b>4*a*c){
            printf("x1=%.5f;x2=%.5f",(-b+sqrt(b*b-4*a*c))/(2*a), (-b-sqrt(b*b-4*a*c))/(2*a));
        }else{
            x = (-b/(2*a));
            if(x==-0.00000)x=0;
            printf("x1=%.5f+%.5fi;x2=%.5f-%.5fi",x,(sqrt(4*a*c-b*b)/(2*a)),x,(sqrt(4*a*c-b*b)/(2*a)));
        }
        return 0;
    }
    

    21:苹果和虫子2

    #include<cstdio>
    #include<iostream>
    #include<cmath>
    using namespace std;
    int main(){
        int n, x, y;
        cin>>n>>x>>y;
        if(y == 0){
            cout<<n<<'
    ';
            return 0;
        }
        int ans = n-((y-1)/x+1);
        if(ans < 0)ans = 0;
        cout<< ans <<'
    ';
        return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/gwj1314/p/10200057.html
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