SELECT a.annual,a.policy_name,b.[value] FROM (SELECT annual,policy_name,[value]=CAST('<v>'+REPLACE([relation],',','</v><v>')+'</v>' AS xml) FROM T_table) a OUTER APPLY (SELECT [value]=T.C.value('.','varchar(50)') FROM a.[value].nodes('/v') AS T(C)) b
表的数据
查询的结果
