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  • 273. Integer to English Words

    Convert a non-negative integer to its english words representation. Given input is guaranteed to be less than 231 - 1.

    Example 1:

    Input: 123
    Output: "One Hundred Twenty Three"
    

    Example 2:

    Input: 12345
    Output: "Twelve Thousand Three Hundred Forty Five"

    Example 3:

    Input: 1234567
    Output: "One Million Two Hundred Thirty Four Thousand Five Hundred Sixty Seven"
    

    Example 4:

    Input: 1234567891
    Output: "One Billion Two Hundred Thirty Four Million Five Hundred Sixty Seven Thousand Eight Hundred Ninety One"

    Approach #1: String. [Java]

    private final String[] LESS_THAN_20 = {"", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen"};
    private final String[] TENS = {"", "Ten", "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety"};
    private final String[] THOUSANDS = {"", "Thousand", "Million", "Billion"};
    
    class Solution {
        public String numberToWords(int num) {
            if (num == 0) return "Zero";
            
            int i = 0;
            String words = "";
            
            while (num > 0) {
                if (num % 1000 != 0)
                    words = helper(num % 1000) + THOUSANDS[i] + " " + words;
                num /= 1000;
                i++;
            }
            
            return words.trim();
        }
        
        private String helper(int num) {
            if (num == 0) 
                return "";
            else if (num < 20) 
                return LESS_THAN_20[num] + " ";
            else if (num < 100)
                return TENS[num / 10] + " " + helper(num % 10);
            else 
                return LESS_THAN_20[num / 100] + " Hundred " + helper(num % 100);
        }
    }
    

      

    Reference:

    https://leetcode.com/problems/integer-to-english-words/discuss/70625/My-clean-Java-solution-very-easy-to-understand

    永远渴望,大智若愚(stay hungry, stay foolish)
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  • 原文地址:https://www.cnblogs.com/h-hkai/p/10715817.html
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