判断 Android 手机是否处于联网状态

Android App的开发大多数情况下都要与网络进行连接，那如何判断网络是否连接，处于何种连接呢？下面是关于连接写的一个方法，可以根据需求做相应的修改：

private String connection(Context context) {
//判断联网，一定要记得写权限<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE"></uses-permission>
    String connectInfo = "网络未连接";
    ConnectivityManager connect = (ConnectivityManager) context
            .getSystemService(Context.CONNECTIVITY_SERVICE);
    NetworkInfo info = connect.getActiveNetworkInfo();
    if(info != null && info.isConnected()){
    //if(info.isAvailable()){//此判断在使用时会有异常，需要处理
        connectInfo = "网络已经连接，";

        //GPS是否打开
        if(isGpsEnabled(this)){
            connectInfo += "GPS已经开启";
        }else {
            connectInfo += "GPS未开启";
        }

        //WiFi是否打开
        if(isWifiEnabled(this,connect)){
            connectInfo += "WIFI开启";
        }else {
            connectInfo += "WIFI未开启";
        }

        int netType = info.getType();
        if(netType == ConnectivityManager.TYPE_WIFI){
            connectInfo += "
当前使用WIFI";
        }else if(netType == ConnectivityManager.TYPE_MOBILE){
            connectInfo += "
当前使用移动连接";
        }else {
            connectInfo += "
当前使用连接是:"+netType;
        }
    }
    return connectInfo;
}

//判断GPS是否打开
public static boolean isGpsEnabled(Context context) {
    LocationManager lm = ((LocationManager) context
            .getSystemService(Context.LOCATION_SERVICE));
    List<String> accessibleProviders = lm.getProviders(true);
    return accessibleProviders != null && accessibleProviders.size() > 0;
}
//判断WIFI是否打开
public static boolean isWifiEnabled(Context context,ConnectivityManager mgrConn) {
    TelephonyManager mgrTel = (TelephonyManager) context
            .getSystemService(Context.TELEPHONY_SERVICE);
    return ((mgrConn.getActiveNetworkInfo() != null && mgrConn
            .getActiveNetworkInfo().getState() == NetworkInfo.State.CONNECTED) || mgrTel
            .getNetworkType() == TelephonyManager.NETWORK_TYPE_UMTS);
}