取三个以上连续的连续的行使得他们的人数大于100
X city built a new stadium, each day many people visit it and the stats are saved as these columns: id, date, people
Please write a query to display the records which have 3 or more consecutive rows and the amount of people more than 100(inclusive).
For example, the table stadium
:
+------+------------+-----------+ | id | date | people | +------+------------+-----------+ | 1 | 2017-01-01 | 10 | | 2 | 2017-01-02 | 109 | | 3 | 2017-01-03 | 150 | | 4 | 2017-01-04 | 99 | | 5 | 2017-01-05 | 145 | | 6 | 2017-01-06 | 1455 | | 7 | 2017-01-07 | 199 | | 8 | 2017-01-08 | 188 | +------+------------+-----------+
For the sample data above, the output is:
+------+------------+-----------+ | id | date | people | +------+------------+-----------+ | 5 | 2017-01-05 | 145 | | 6 | 2017-01-06 | 1455 | | 7 | 2017-01-07 | 199 | | 8 | 2017-01-08 | 188 | +------+------------+-----------+
SELECT DISTINCT t1.* FROM stadium t1, stadium t2, stadium t3 WHERE t1.people >= 100 AND t2.people >= 100 AND t3.people >= 100 AND ( ( t1.id - t2.id = 1 AND t1.id - t3.id = 2 AND t2.id - t3.id = 1 ) OR ( t2.id - t1.id = 1 AND t2.id - t3.id = 2 AND t1.id - t3.id = 1 ) OR ( t3.id - t2.id = 1 AND t2.id - t1.id = 1 AND t3.id - t1.id = 2 ) ) ORDER BY t1.id