实验吧密码学：RSAROLL

原题：

{920139713,19}
 
704796792
752211152
274704164
18414022
368270835
483295235
263072905
459788476
483295235
459788476
663551792
475206804
459788476
428313374
475206804
459788476
425392137
704796792
458265677
341524652
483295235
534149509
425392137
428313374
425392137
341524652
458265677
263072905
483295235
828509797
341524652
425392137
475206804
428313374
483295235
475206804
459788476
306220148

题目给出了n和e，首先分解质因数

可以在线分解：http://www.atool.org/quality_factor.php

接下来就是通过程序实现解密：

#-*- coding:utf-8 -*-
#博客园 hell0_w

import gmpy2
import libnum

p = 18443
q = 49891
e = 19
list = []
list1 = []
f = open('rsa.txt','rb')
for line in f.readlines():
    line = line.strip('
')
    list.append(line)


n = p * q
l = (p-1) * (q-1)

d = gmpy2.invert(e,l)
for i in range(len(list)):
    m = pow(int(list[i]),d,n)
    list1.append(libnum.n2s(m))

print ''.join(list1)

。。。