华为机试——删除含7元素和被7整除的元素

C_C++_WP_04. Remove Particular Elements in an Array

• Description:

Input an array, in which each element must be greater than 0 and less than 999. Then, remove following elements:

l Elements that can be evenly divided by 7

l Elements containing the digit 7.

The number of elements left in the array is returned. The order of the remaining elements in the array does not change.

• Function to be implemented:

int vDelete7Data(int arrIn[],int Num, int arrOut[]);

[Input] arrIn: array consisting of integers

Num: number of elements in the array

[Output] arrOut: array with the particular elements removed

The output is the number of elements in the array with the particular elements removed by the function.

[Note] The order of the numbers in the array must not change.

• Example 1

Input: 1,2,3,5,4,6,7,14,10

Output: 1,2,3,5,4,6,10

The value 7 is returned.

• Example 2

Input: 73,64,70,75,6,3

Output: 64,6,3

The value 3 is returned.

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#include <iostream> using namespace std;   int vDelete7Data(int arrIn[],int Num, int arrOut[]) {     if ((arrIn == NULL) || (Num <= 0) || arrOut == NULL)     {         return 0;     }       int count = 0;     for (int i = 0; i < Num; i++)     {         int tmp = arrIn[i];           if (tmp % 7 == 0)         {             continue;         }         else         {             while ((tmp != 0) && (tmp % 10 != 7))             {                 tmp /= 10;             }             if (tmp == 0)             {                 *arrOut = arrIn[i];                 arrOut++;                 count++;             }             else             {                 continue;             }         }     }       return count; }   int main() {       int arrIn[] = {73,64,70,75,6,3};     int arrOut[10] = {0};     cout << vDelete7Data(arrIn,6, arrOut) << endl;       for (int i = 0; arrOut[i] != 0; i++)     {         cout << arrOut[i] << endl;     }     return 0; }