zoukankan      html  css  js  c++  java
  • [leetcode-200-Number of Islands]

    Given a 2d grid map of '1's (land) and '0's (water), count the number of islands. An island is surrounded by water and is formed by connecting adjacent lands horizontally or vertically. You may assume all four edges of the grid are all surrounded by water.

    Example 1:

    11110
    11010
    11000
    00000

    Answer: 1

    Example 2:

    11000
    11000
    00100
    00011

    Answer: 3

    思路:

    DFS,用一个标记visited数组记录。

    void dfsisland(vector<vector<char>>& grid, vector<vector<bool>>& visited,int i,int j)
         {
             int m = grid.size(), n = grid[0].size();
             if (i < 0 || i >= m || j < 0 || j >= n || visited[i][j] || grid[i][j] == '0')return;
             visited[i][j] = true;
             dfsisland(grid, visited, i + 1, j);
             dfsisland(grid, visited, i - 1, j);
             dfsisland(grid, visited, i, j + 1);
             dfsisland(grid, visited, i, j - 1);
         }
         int numIslands(vector<vector<char>>& grid)
         {
             if (grid.empty())return 0;
             int m = grid.size(), n = grid[0].size();
             vector<vector<bool>>visited(m, vector<bool>(n, false));
             int ret = 0;
             for (int i = 0; i < m;i++)
             {
                 for (int j = 0; j < n;j++)
                 {
                     if (grid[i][j] == '1' && !visited[i][j])
                     {
                         dfsisland(grid, visited,i,j);
                         ret++;
                     }
                 }
             }
             return ret;
         }
  • 相关阅读:
    2014--My Plan
    C++操作xls
    fail2ban[防止linux服务器被暴力破解]
    8.1向上转型
    寒假的一个月--实现自己的五部狂奏曲
    浅谈《think in java》:二 一切都是对象
    浅谈《think in java》:一 对象导论总结
    增加Myecllipse内存
    java 容器 集合 用法
    SVN用户切换
  • 原文地址:https://www.cnblogs.com/hellowooorld/p/7153046.html
Copyright © 2011-2022 走看看