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  • [leetcode-655-Print Binary Tree]

    Print a binary tree in an m*n 2D string array following these rules:

    1. The row number m should be equal to the height of the given binary tree.
    2. The column number n should always be an odd number.
    3. The root node's value (in string format) should be put in the exactly middle of the first row it can be put. The column and the row where the root node belongs will separate the rest space into two parts (left-bottom part and right-bottom part). You should print the left subtree in the left-bottom part and print the right subtree in the right-bottom part. The left-bottom part and the right-bottom part should have the same size. Even if one subtree is none while the other is not, you don't need to print anything for the none subtree but still need to leave the space as large as that for the other subtree. However, if two subtrees are none, then you don't need to leave space for both of them.
    4. Each unused space should contain an empty string "".
    5. Print the subtrees following the same rules.

    Example 1:

    Input:
         1
        /
       2
    Output:
    [["", "1", ""],
     ["2", "", ""]]
    

    Example 2:

    Input:
         1
        / 
       2   3
        
         4
    Output:
    [["", "", "", "1", "", "", ""],
     ["", "2", "", "", "", "3", ""],
     ["", "", "4", "", "", "", ""]]
    

    Example 3:

    Input:
          1
         / 
        2   5
       / 
      3 
     / 
    4 
    Output:
    
    [["",  "",  "", "",  "", "", "", "1", "",  "",  "",  "",  "", "", ""]
     ["",  "",  "", "2", "", "", "", "",  "",  "",  "",  "5", "", "", ""]
     ["",  "3", "", "",  "", "", "", "",  "",  "",  "",  "",  "", "", ""]
     ["4", "",  "", "",  "", "", "", "",  "",  "",  "",  "",  "", "", ""]]
    

    Note: The height of binary tree is in the range of [1, 10].

    思路:

    观察例子可以发现,行m就是树的高度h,列n就是2h-1,那么首先构造一个二维数组ret[m][n].用“”初始化。

    观察得到,每一个深度为d的树节点t都在ret所在的行为d(假设下标从1开始)的中间。而t的左孩子,则深度为t+1,所在的行下标范围[left,mid-1]

    可以递归。

    int maxDepth(TreeNode *root) 
    {
          int depth;  
          if(root==NULL)return 0;  
          else{  
          depth=(maxDepth(root->left)>maxDepth(root->right)?  
              maxDepth(root->left):maxDepth(root->right))+1;  
          return depth;
          }    
    }
    void printTree(vector<vector<string>>& ret,TreeNode* root,int leftIndex,int rightIndex,int curDepth,int maxDepth)
    {
      if(curDepth>maxDepth || root==NULL||leftIndex>rightIndex) return;
      int mid = (leftIndex+rightIndex)/2;
      ret[curDepth-1][mid] = to_string(root->val);
      printTree(ret,root->left,leftIndex,mid-1,curDepth+1,maxDepth);
      printTree(ret,root->right,mid+1,rightIndex,curDepth+1,maxDepth);
    }
    vector<vector<string>> printTree(TreeNode* root) 
    {
            int depth = maxDepth(root);
        if(depth == 0) return {{}};
        
        vector<vector<string>> ret(depth,vector<string>(pow(2,depth)-1,""));
        
        printTree(ret,root,0,pow(2,depth)-1-1,1,depth);
        return ret;
    }
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  • 原文地址:https://www.cnblogs.com/hellowooorld/p/7294234.html
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