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  • ArrayList LinkedList Vector

    ArrayList与LinkedList

    ArrayList 通过数组实现,LinkedList 通过双向链表实现

    get/set:ArrayList直接通过下标在数组中取,LinkedList需要从头/尾遍历到index

    add/remove:ArrayList需要将index之后的元素都复制一遍,如果需要扩容需要将原数组所有元素复制到新数组

          (如果一个包含大量元素的ArrayList对象,数组扩容1.5倍,那么最终将有很大的空间会被浪费掉,调用trimToSize方法去掉浪费掉的空间)

          LinkedList需要从头/尾遍历到该元素并操作前后节点

    get

        /**
         * ArrayList get
         * 直接通过下标在数组中取
         */
        public E get(int index) {
            rangeCheck(index);
            return elementData(index);
        }
        E elementData(int index) {
            return (E) elementData[index];
        }
        
        /**
         * LinkedList get
         * 从头/尾遍历到index
         */
        public E get(int index) {
            checkElementIndex(index);
            return node(index).item;
        }
        Node<E> node(int index) {
            if (index < (size >> 1)) {
                Node<E> x = first;
                for (int i = 0; i < index; i++)
                    x = x.next;
                return x;
            } else {
                Node<E> x = last;
                for (int i = size - 1; i > index; i--)
                    x = x.prev;
                return x;
            }
        }

    set

        /**
         * ArrayList set
         * 同get
         */
        public E set(int index, E element) {
            rangeCheck(index);
            E oldValue = elementData(index);
            elementData[index] = element;
            return oldValue;
        }
        
        /**
         * LinkedList
         * 同get
         */
        public E set(int index, E element) {
            checkElementIndex(index);
            Node<E> x = node(index);
            E oldVal = x.item;
            x.item = element;
            return oldVal;
        }

    add

        /**
         * ArrayList数组扩容
         * 1.需求容量 <= elementData.length, 不需要扩容
         * 2.newCapacity = 1.5*oldCapacity 或 需求容量
         * 3.扩容之后, 原数组元素复制到新数组
         */
        private void ensureCapacityInternal(int minCapacity) {
            ensureExplicitCapacity(calculateCapacity(elementData, minCapacity));
        }
        private void ensureExplicitCapacity(int minCapacity) {
            modCount++;
            if (minCapacity - elementData.length > 0)
                grow(minCapacity);
        }
        private void grow(int minCapacity) {
            // overflow-conscious code
            int oldCapacity = elementData.length;
            int newCapacity = oldCapacity + (oldCapacity >> 1);
            if (newCapacity - minCapacity < 0)
                newCapacity = minCapacity;
            if (newCapacity - MAX_ARRAY_SIZE > 0)
                newCapacity = hugeCapacity(minCapacity);
            // minCapacity is usually close to size, so this is a win:
            elementData = Arrays.copyOf(elementData, newCapacity);
        }
        
        /**
         * ArrayList add(e)
         * 1.数组扩容(需要的话)
         * 2.添加e
         */
        public boolean add(E e) {
            ensureCapacityInternal(size + 1);
            elementData[size++] = e;
            return true;
        }
        
        /**
         * ArrayList add(index, e)
         * 1.数组可能要扩容
         * 2.index之后的元素复制一遍到index+1之后
         * 3.elementData[index] = e;
         */
        public void add(int index, E element) {
            rangeCheckForAdd(index);
            ensureCapacityInternal(size + 1);  // Increments modCount!!
            System.arraycopy(elementData, index, elementData, index + 1, size - index);
            elementData[index] = element;
            size++;
        }
        
        
        /**
         * LinkedList add(e)
         * 直接与最后一个元素互相添加节点
         */
        public boolean add(E e) {
            linkLast(e);
            return true;
        }    
        void linkLast(E e) {
            final Node<E> l = last;
            final Node<E> newNode = new Node<>(l, e, null);
            last = newNode;
            if (l == null)
                first = newNode;
            else
                l.next = newNode;
            size++;
            modCount++;
        }
        
        /**
         * LinkedList add(index, e)
         * 1.从头/尾遍历到index
         * 2.互相添加节点
         */
        public void add(int index, E element) {
            checkPositionIndex(index);
            if (index == size)
                linkLast(element);
            else
                linkBefore(element, node(index));
        }
        void linkBefore(E e, Node<E> succ) {
            // assert succ != null;
            final Node<E> pred = succ.prev;
            final Node<E> newNode = new Node<>(pred, e, succ);
            succ.prev = newNode;
            if (pred == null)
                first = newNode;
            else
                pred.next = newNode;
            size++;
            modCount++;
        }

    remove

        /**
         * ArrayList remove(index)
         * 1.index+1之后的元素复制到index之后
         * 2.elementData[--size] = null
         */
        public E remove(int index) {
            rangeCheck(index);
    
            modCount++;
            E oldValue = elementData(index);
    
            int numMoved = size - index - 1;
            if (numMoved > 0)
                System.arraycopy(elementData, index+1, elementData, index, numMoved);
            elementData[--size] = null; // clear to let GC do its work
            return oldValue;
        }
        
        /**
         * ArrayList remove(Object)
         * 1.遍历数组找到Object
         * 2.index+1之后的元素复制到index之后
         * 3.elementData[--size] = null
         */
        public boolean remove(Object o) {
            if (o == null) {
                for (int index = 0; index < size; index++)
                    if (elementData[index] == null) {
                        fastRemove(index);
                        return true;
                    }
            } else {
                for (int index = 0; index < size; index++)
                    if (o.equals(elementData[index])) {
                        fastRemove(index);
                        return true;
                    }
            }
            return false;
        }
        
        /**
         * LinkedList remove(index)
         * 1.从头/尾遍历到index
         * 2.将index的前后节点相关联
         */
        public E remove(int index) {
            checkElementIndex(index);
            return unlink(node(index));
        }
        E unlink(Node<E> x) {
            // assert x != null;
            final E element = x.item;
            final Node<E> next = x.next;
            final Node<E> prev = x.prev;
    
            if (prev == null) {
                first = next;
            } else {
                prev.next = next;
                x.prev = null;
            }
    
            if (next == null) {
                last = prev;
            } else {
                next.prev = prev;
                x.next = null;
            }
    
            x.item = null;
            size--;
            modCount++;
            return element;
        }
        
        /**
         * LinkedList remove(Object)
         * 1.从头/尾遍历到object
         * 2.将object的前后节点相关联
         */
        public boolean remove(Object o) {
            if (o == null) {
                for (Node<E> x = first; x != null; x = x.next) {
                    if (x.item == null) {
                        unlink(x);
                        return true;
                    }
                }
            } else {
                for (Node<E> x = first; x != null; x = x.next) {
                    if (o.equals(x.item)) {
                        unlink(x);
                        return true;
                    }
                }
            }
            return false;
        }

    ArrayList与Vector

    实现原理一样

    主要区别:

      ①线程安全:Vector增删改查的方法都有synchronized,线程安全,但性能较ArrayList差

      ②扩容:ArrayList每次扩1.5倍(int newCapacity = oldCapacity + (oldCapacity >> 1))

          Vector默认扩成原来的2倍(int newCapacity = oldCapacity + ((capacityIncrement > 0) ? capacityIncrement : oldCapacity))

    参考资料:

    ArrayList vs LinkedList vs Vector 区别中进行了实际的性能测试

    Java 集合系列08之 List总结(LinkedList, ArrayList等使用场景和性能分析)

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  • 原文地址:https://www.cnblogs.com/hexinwei1/p/9699636.html
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