康托展开+反向bfs
hdu 1043
题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=1043
#include <iostream>
#include <cstdio>
#include <queue>
using namespace std;
struct Step_s{
int parent;
char dir;
}step_set[500010];
typedef struct Node_s{
int board[10];
int x_index;
int child;
}Node;
int dir[4][2] = {{1,0},{-1,0},{0,1},{0,-1}};
int fac[10];
void set_fac()
{
fac[0] = 1;
for(int i=1;i<=8;i++)
{
fac[i] = fac[i-1]*i;
}
}
int board_hash(int board[])
{
int ans = 0;
for(int i=0;i<9;i++)
{
int k = 0;
for(int j=i+1;j<9;j++)
{
if(board[j]<board[i])
k++;
}
ans += k * fac[8-i];
}
return ans;
}
void bfs(int finish[])
{
queue<Node> Q;
Node current;
int tx,ty,temp;
for(int i=0;i<9;i++)
{
current.board[i] = finish[i];
}
current.x_index = 8,current.child = 0;
step_set[current.child].parent = 0;
Q.push(current);
while(Q.size())
{
current = Q.front();
Q.pop();
for(int i=0;i<4;i++)
{
Node Next = current;
tx = current.x_index % 3 + dir[i][0];
ty = current.x_index / 3 + dir[i][1];
if(tx>=0&&ty>=0&&tx<3&&ty<3)
{
Next.x_index = ty * 3 + tx;
temp = Next.board[Next.x_index];
Next.board[Next.x_index] = Next.board[current.x_index];
Next.board[current.x_index] = temp;
Next.child = board_hash(Next.board);
if(step_set[Next.child].parent == -1)
{
step_set[Next.child].parent = current.child;
if(i == 0)step_set[Next.child].dir = 'l';
if(i == 1)step_set[Next.child].dir = 'r';
if(i == 2)step_set[Next.child].dir = 'u';
if(i == 3)step_set[Next.child].dir = 'd';
Q.push(Next);
}
}
}
}
}
int main() {
int i,j,finish[10],board_input[10];
string ch;
set_fac();
for(i=0;i<9;i++)
{
finish[i] = i + 1;
}
for(i=0;i<500000;i++)
{
step_set[i].parent = -1;
}
bfs(finish);
while(getline(cin,ch))
{
int s;
for(i=0,j=0;i<ch.size();i++)
{
if(ch[i] == 'x')
{
board_input[j++] = 9;
}
else if(ch[i] >= '1' && ch[i] <= '8')
{
board_input[j++] = ch[i] - '0';
}
}
s = board_hash(board_input);
if(step_set[s].parent== -1 )
{
printf("unsolvable
");
continue;
}
while(s!=0)
{
printf("%c",step_set[s].dir);
s = step_set[s].parent;
}
puts("");
}
return 0;
}