zoukankan      html  css  js  c++  java
  • ZOJ 1610 Count the Colors(线段树,区间覆盖,单点查询)

    Count the Colors

    Time Limit: 2 Seconds      Memory Limit: 65536 KB

    Painting some colored segments on a line, some previously painted segments may be covered by some the subsequent ones.

    Your task is counting the segments of different colors you can see at last.


    Input

    The first line of each data set contains exactly one integer n, 1 <= n <= 8000, equal to the number of colored segments.

    Each of the following n lines consists of exactly 3 nonnegative integers separated by single spaces:

    x1 x2 c

    x1 and x2 indicate the left endpoint and right endpoint of the segment, c indicates the color of the segment.

    All the numbers are in the range [0, 8000], and they are all integers.

    Input may contain several data set, process to the end of file.


    Output

    Each line of the output should contain a color index that can be seen from the top, following the count of the segments of this color, they should be printed according to the color index.

    If some color can't be seen, you shouldn't print it.

    Print a blank line after every dataset.


    Sample Input

    5
    0 4 4
    0 3 1
    3 4 2
    0 2 2
    0 2 3
    4
    0 1 1
    3 4 1
    1 3 2
    1 3 1
    6
    0 1 0
    1 2 1
    2 3 1
    1 2 0
    2 3 0
    1 2 1


    Sample Output

    1 1
    2 1
    3 1

    1 1

    0 2
    1 1

    用col[rt]记录区间的颜色,-1表示多个颜色。。。

    #include <bits/stdc++.h>
    using namespace std;
    #define root 1,n,1
    #define lson l,mid,rt<<1
    #define rson mid+1,r,rt<<1|1
    #define lr rt<<1
    #define rr rt<<1|1
    const int N =  20010;
    int n , m , col[N<<2],tag[N<<2] ;
    
    void Down( int l , int r , int rt ) {
        if( col[rt] != -1 ) col[lr] = col[rr] = col[rt] ;
    }
    void Up( int rt ){
        if( col[lr] == col[rr] ) col[rt] = col[lr];
        else col[rt] = -1 ;
    }
    void build( int l , int r , int rt ){
        col[rt] = -1 ;
        if( l == r ) return ;
        int mid = (l+r)>>1;
        build(lson),build(rson);
    }
    void update( int l , int r , int rt , int L , int R , int c ) {
        if( L == l && r == R ) {
            col[rt] = c ; return ;
        }
        if( col[rt] == c ) return ;
        else Down( l,r,rt ) , col[rt] = -1 ;
        int mid = (l+r)>>1;
        if( R <= mid ) update(lson,L,R,c);
        else if( L > mid ) update(rson,L,R,c);
        else update(lson,L,mid,c) , update(rson,mid+1,R,c);
        Up(rt);
    }
    
    int query( int l , int r , int rt , int x ) {
        if( col[rt] != -1 || l == r ) return col[rt];
        Down(l,r,rt);
        int mid = (l+r)>>1;
        if( x <= mid ) return query(lson,x);
        else return query(rson,x);
    }
    
    int main()
    {
        int _ ,x ,y , c ;
        n = 8888;
        while( ~scanf("%d",&m) ) {
            memset( tag , 0, sizeof tag );
            build(root);
            while( m-- ) {
                scanf("%d%d%d",&x,&y,&c);x++;
                update(root,x,y,c);
            }
            int last = -1 , now ;
            for( int i = 1 ; i <= n ; ++i ) {
                now = query(root,i);
                if( last == -1 ) { last = now ; continue ; }
                if( last == now ) continue ;
                else tag[last]++; last=now;
            }
            for( int i = 0 ; i <= n ; ++i ) if( tag[i] ){
                printf("%d %d
    ",i,tag[i]);
            }printf("
    ");
        }
    }
    View Code
    only strive for your goal , can you make your dream come true ?
  • 相关阅读:
    iOS 方便的宏定义
    IOS 推送消息 php做推送服务端
    iOS 7 动画UIDynamicAnimator
    iOS 适配
    ios 实现简单的解析xml网页
    用 MPMoviePlayerController 实现简单的视频下载播放功能
    ios 自定义弹出对话框效果
    ios国外大神
    git学习
    ios 7UI适配方法
  • 原文地址:https://www.cnblogs.com/hlmark/p/4248171.html
Copyright © 2011-2022 走看看