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  • 多元线性回归

    package com.smart.test;
    
    public class Algorithm
    {
        /**
         * 一元线性回归分析
         * 
         * @param x[n] 存放自变量x的n个取值
         * @param y[n] 存放与自变量x的n个取值相对应的随机变量y的观察值
         * @param n    观察点数
         * @param a[2]   a(0) 返回回归系数b ,a(1)返回回归系数a
         */
        public static void lineareEquation(double[] x, double[] y, int n, double[] a)
        {
            int i;
            double xx, yy, e, f, q, s;
            xx = 0.0;
            yy = 0.0;
            for (i = 0; i <= n - 1; i++)
            {
                xx = xx + x[i] / n;
                yy = yy + y[i] / n;
            }
            e = 0.0;
            f = 0.0;
            for (i = 0; i <= n - 1; i++)
            {
                q = x[i] - xx;
                e = e + q * q;
                f = f + q * (y[i] - yy);
            }
            a[1] = f / e;
            a[0] = yy - a[1] * xx;
            q = 0.0;
            for (i = 0; i <= n - 1; i++)
            {
                s = a[1] * x[i] + a[0];
                q = q + (y[i] - s) * (y[i] - s);
                e = Math.abs(y[i] - s);
            }
        }
        /**
         * 多元一次方程求解
         * 
         * @param a 系数数组
         * @param b 结果数组
         * @return 解答
         */
        public static double[] multiLinearEquationGroup(double[][] a, double[] b)
        {
            if (a == null || b == null || a.length == 0 || a.length != b.length) return null;
            for (double[] x : a)
            {
                if (x == null || x.length != a.length) return null;
            }
    
            int len = a.length - 1;
            double[] result = new double[a.length];
    
            if (len == 0)
            {
                result[0] = b[0] / a[0][0];
                return result;
            }
    
            double[][] aa = new double[len][len];
            double[] bb = new double[len];
            int posx = -1, posy = -1;
            for (int i = 0; i <= len; i++)
            {
                for (int j = 0; j <= len; j++)
                    if (a[i][j] != 0.0d)
                    {
                        posy = j;
                        break;
                    }
                if (posy != -1)
                {
                    posx = i;
                    break;
                }
            }
            if (posx == -1) return null;
    
            int count = 0;
            for (int i = 0; i <= len; i++)
            {
                if (i == posx) continue;
                bb[count] = b[i] * a[posx][posy] - b[posx] * a[i][posy];
                int count2 = 0;
                for (int j = 0; j <= len; j++)
                {
                    if (j == posy) continue;
                    aa[count][count2] = a[i][j] * a[posx][posy] - a[posx][j] * a[i][posy];
                    count2++;
                }
                count++;
            }
    
            double[] result2 = multiLinearEquationGroup(aa, bb);
    
            double sum = b[posx];
            count = 0;
            for (int i = 0; i <= len; i++)
            {
                if (i == posy) continue;
                sum -= a[posx][i] * result2[count];
                result[i] = result2[count];
                count++;
            }
            result[posy] = sum / a[posx][posy];
    
            return result;
        }
    
        /**
         * @param args
         */
        public static void main(String[] args)
        {
            
            /**
             * 一元回归
             */
            double[] a = new double[2];
            double[] x = { 0.0,0.1,0.2,0.3,0.4,0.5,0.6,0.7,0.8,0.9,1.0};
            double[] y = { 2.75,2.84,2.965,3.01,3.20,3.25,3.38,3.43,3.55,3.66,3.74};
            Algorithm.lineareEquation(x,y,11,a);
            System.out.println("a="+a[1]+" b="+a[0]);
            /**
             * 多元回归
             */
    //        double[] r = multiLinearEquationGroup(new double[][] { { 1, 2, 3, 1 }, { 2, 0, 1, 0 }, { 5, 2, 0, 0 }, { 7, 1, 1, 0 } }, new double[] { 18, 5, 9, 12 });
    //        for (int i = 0; i < r.length; i++)
    //        {
    //            System.out.println(r[i]);
    //        }
        }
    }
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  • 原文地址:https://www.cnblogs.com/hnhcc39/p/2933856.html
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